Answer:
see explanation below
Explanation:
First, you are not providing any data of the bromide solution to calculate the mass. So, in order to help you, I will take some random values from a similar exercise, so you can solve this later with your data.
Let's suppose you add 360 mL of a 1.45 mol/L of a calcium bromide solution into the flask. To calculate the mass it was added, you need to calculate first the moles added. This can be done with the following expression:
M = n/V
Where:
M: molarity of solution
n: moles of solution
V: volume (in liters) of solution
here, you have to solve for n, so:
n = M*V
replacing the above data you have:
n = 1.45 * (0.360) = 0.522 moles
Now that we have the moles, you can calculate the mass by the following expression:
m = n * MM
Where MM it's the molar mass of calcium bromide. The reported MM of calcium bromide is 199.89 g/mol, so replacing:
m = 199.89 * 0.522
m = 104.34 g
And this is the mass that was added of the solution. As I stated before, use your data in this procedure, and you should get an accurate result.
