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Ira Lisetskai [31]
3 years ago
7

During an endothermic phase change, what happens to the potential energy and the kinetic energy?

Chemistry
2 answers:
Dovator [93]3 years ago
7 0
The correct answer should be that Potential energy increases, and kinetic energy increases, since they both increase as the temperature changes.
m_a_m_a [10]3 years ago
7 0

Answer:

D.) Potential energy increases, and kinetic energy stays the same

Explanation:

edge 2020

hope this helps!!

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When mixtures of gaseous h2 and gaseous cl2 react, a product forms that has the same properties regardless of the relative amoun
lilavasa [31]
According to Dalton's Atomic Theory, the <em>Law of Definite Proportion is applied when a compound is always made up by a fixed fraction of its individual elements.</em> This is manifested by the balancing of the reaction.

The reaction for this problem is:

H₂ + Cl₂ → 2 HCl

1 mol of H₂ is needed for every 1 mole of Cl₂. Assuming these are ideal gases, the moles is equal to the volume. So, if equal volumes of the reactants are available, they will produce twice the given volumes of HCl.
4 0
3 years ago
What is gold atomic number
Korolek [52]

Answer:

79

Explanation:

6 0
3 years ago
The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calc
jek_recluse [69]

Answer: K_{sp}=1.25\times 10^{-14}

pK_{sp}=13.90

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as K_{sp}  

The equation for the ionization of magnesium phosphate is given as:

Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}

 When the solubility of Mg_3(PO_4)_2 is S moles/liter, then the solubility of Mg^{2+} will be 3S moles\liter and solubility of PO_4^{3-} will be 2S moles/liter.

Thus S = 0.173 g/L or \frac{0.173g/L}{262.8g/mol}=0.00065mol/L

K_{sp}=(3S)^3\times (2S)^2

K_{sp}=108S^5

K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}

pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90

5 0
3 years ago
If the titrant has a molarity of 0.1000 m and there are 45.00 ml of analyte present, what is the molarity of the analyte?
marysya [2.9K]
Given: 

Concentration of titrant = 0.1000 M
Volume of titrant = 45 mL

The molarity of analyte depends on the amount of the analyte present in the titrated solution. If the amount of analyte is 20 mL, then its concentration is:

45ml * 0.10 M = C analyte * 20 ml

C analyte = 0.225 M
4 0
3 years ago
A metamorphic rock can also be thought of as a rock that changes. What causes the rock to change?
Nana76 [90]

Answer:

its ethier b or c

Explanation:

5 0
2 years ago
Read 2 more answers
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