A six-pack of soda costs $3.36 How much does one soda cost?

What is a exponent please don’t use the internet and don’t give me a wrong answer

My name is Ann [436]

Answer:

An exponent can be any small number, which is almost always in the top write corner of a whole number.

Step-by-step explanation:

For example, 4(6). the 6 would be in the top right corner. This is an easier way of writing 4x4x4x4x4x4.

7 0

3 years ago

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6) There are many cylinders with a height of 4 inches.

diamong [38]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

height of cylinder h = 4 inches

Given the table

Radius Volume

1 ___

2 ___

3 ___

Determining the Volume of the cylinder when r = 1 inch and h = 4 inches

Given

h = 4 inches

r = 1 inch

Using the formula to determine the volume of the cylinder

V = πr²h

V = 3.14×(1)²×(4)

V = 3.14 × 1 × 4

V = 12.56

V ≈ 13 (nearst cubic inch)

Therefore, the volume of cylinder when h = 4 inches and r = 1 inch will be:

V ≈ 13 cubic inches (nearest cubic inch)

Determining the Volume of the cylinder when r = 2 inches and h = 4 inches

Given

h = 4 inches

r = 2 inch

Using the formula to determine the volume of the cylinder

V = πr²h

V = 3.14×(2)²×(4)

V = 3.14 × 4 × 4

V = 50.24

V ≈ 50 (nearst cubic inch)

Therefore, the volume of cylinder when h = 4 inches and r = 2 inches will be:

V ≈ 50 cubic inches (nearest cubic inch)

Determining the Volume of the cylinder when r = 3 inches and h = 4 inches

Given

h = 4 inches

r = 3 inch

Using the formula to determine the volume of the cylinder

V = πr²h

V = 3.14×(3)²×(4)

V = 3.14 × 9 × 4

V = 113.04

V ≈ 113 (nearst cubic inch)

Therefore, the volume of cylinder when h = 4 inches and r = 3 inches will be:

V ≈ 113 cubic inches (nearest cubic inch)

Therefore, we complete the table conclude such as:

Radius Volume

1 13

2 50

3 113

5 0

2 years ago

What is 150 percent of 22

anastassius [24]

Answer:

it would be 33 i think

7 0

2 years ago

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Help please, hurry

Lady bird [3.3K]

The answer would be B

8 0

3 years ago

If the solution to y=4x+3 is (4,16) what would the steps needed to get (4,16) be?

Ainat [17]

<span>Simplifying x4 = 16
Solving x4 = 16
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Simplifying x4 = 16
Reorder the terms: -16 + x4 = 16 + -16
Combine like terms: 16 + -16 = 0 -16 + x4 = 0
Factor a difference between two squares. (4 + x2)(-4 + x2) = 0
Factor a difference between two squares. (4 + x2)((2 + x)(-2 + x)) = 0
Subproblem 1

Set the factor '(4 + x2)' equal to zero and attempt to solve:
Simplifying 4 + x2 = 0 Solving 4 + x2 = 0
Move all terms containing x to the left, all other terms to the right.
Add '-4' to each side of the equation. 4 + -4 + x2 = 0 + -4
Combine like terms: 4 + -4 = 0 0 + x2 = 0 + -4 x2 = 0 + -4
Combine like terms: 0 + -4 = -4 x2 = -4
Simplifying x2 = -4
The solution to this equation could not be determined.
This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(2 + x)' equal to zero and attempt to solve:
Simplifying 2 + x = 0 Solving 2 + x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-2' to each side of the equation. 2 + -2 + x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + x = 0 + -2 x = 0 + -2
Combine like terms: 0 + -2 = -2 x = -2 Simplifying x = -2

Sub-problem 3

Set the factor '(-2 + x)' equal to zero and attempt to solve:
Simplifying -2 + x = 0 Solving -2 + x = 0
Move all terms containing x to the left, all other terms to the right.
Add '2' to each side of the equation. -2 + 2 + x = 0 + 2
Combine like terms: -2 + 2 = 0 0 + x = 0 + 2 x = 0 + 2
Combine like terms: 0 + 2 = 2 x = 2 Simplifying x = 2Solutionx = {-2, 2}</span>

8 0

3 years ago