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REY [17]
3 years ago
7

Now consider the quantum theory of conduction. At low temperatures, with scattering by lattice vibrations (phonons) not yet impo

rtant,  ~ T. The residual resistivity, 0, as T -> 0 (the text calls this “I ”) is dependent on scattering by defects (impurities, . . .). If the lattice is ‘perfectly ordered’, then  can approach infinity (or at least the size of the metal.) The residual resistivity is a measure of the purity of the sample. A relatively good sample of Cu has 0=2 10-11m.a.) If the Fermi velocity, uF, of Cu is 1.57 106 m/s, and =2 10-11m, according to eq. 10-25 what is the mean free path  in units of m? (Assume Cu is monovalent, i. e. each atom contributes 1 electron to the conduction.) (show how the units come out to give units of length in the end.)
Chemistry
1 answer:
nydimaria [60]3 years ago
4 0

Answer:

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Explanation:

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kap26 [50]
<h3>Answer:</h3>

2.125 g

<h3>Explanation:</h3>

We have;

  • Mass of NaBr sample is 11.97 g
  • % composition by mass of Na in the sample is 22.34%

We are required to determine the mass of 9.51 g of a NaBr sample.

  • Based on the law of of constant composition, a given sample of a compound will always contain the sample percentage composition of a given element.

In this case,

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A sample of 9.51 g of NaBr will also contain 22.345 of Na by mass

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% composition of an element by mass = (Mass of element ÷ mass of the compound) × 100

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Mass of the element = (% composition of an element × mass of the compound) ÷ 100

Therefore;

Mass of sodium = (22.34% × 9.51 g) ÷ 100

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How does iodine help in promoting thyroid health​
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Explanation:

A.) is incorrect because this is not testable. Rather, it is just an opinion that cannot be proven correct or incorrect.

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