Answer:
to change an atom labeled + ion or -ion into a neutral atom, an electron is either added or removed from it
In order to find the two statements, we must first define what the enthalpy of formation and the enthalpy of reaction mean.
Enthalpy of formation:
The change in enthalpy when one mole of substance is formed from its constituent elemetns at standard state.
Enthalpy of reaction:
The change in enthalpy when a reaction occurs and the reactants and products are in their standard states.
Now, we check the statements. The true ones are:
The Hrxn for C(s) + O₂(g) → CO₂(g) is the same as Hf for CO₂
This is true because the formation of carbon dioxide requires carbon and oxygen in their standard states.
The Hf for Br₂<span>(l) is 0 kJ/mol by definition.
Because the bromine is present in its standard state, the enthalpy of formation is 0.
</span><span>The Hrxn for the reaction 1.5H</span>₂<span>(g) + 0.5N</span>₂<span>(g) </span>→ <span>NH</span>₃<span>(g) is the same as the Hf for NH</span>₃<span>(g)
The reactants and products are present in their standard state, and the reaction is the same as the one occurring during the formation of ammonia.
</span>
Answer:
0.897 J/g.⁰C
Explanation:
Given the following data:
m = 170 g (mass)
ΔT = 20.0⁰C (change in temperature)
q = 3050 J (amount of heat)
The amount of heat (q) is calculated as follows:
q = m x Cp x ΔT
Thus, we introduce the data in the mathematical expression to calculate the specific heat (Cp):
Cp = q/(m x ΔT) = 3050 J/(170 g x 20.0⁰C) = 0.897 J/g.⁰C
Answer:
water and vinegar
:salad
Explanation:
There is two kind of mixture the heterogeneous and homogeneous mixture.Which water and vinegar is the homogeneous and the salad is heterogeneous mixture based on my example above.
