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Naddika [18.5K]
3 years ago
9

The higher up you go, it gets harder to breathe because air is less dense which means that there are ____________ molecules of o

xygen to breathe into our lungs.
PLEASE HELP!
Chemistry
2 answers:
Papessa [141]3 years ago
7 0
Less is the word to ur question
mamaluj [8]3 years ago
7 0
The answer should be fewer based on the question. The oxygen molecules in the air are spread more thinly and therefore you take in less oxygen molecules per breath. Hope this helps!
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Calculate the number of atoms of sodium in a 4.5-gram sample
allochka39001 [22]

Answer:

1.18×10²³ atoms.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms.

From the above concept, 1 mole of sodium also contains 6.02×10²³ atoms.

1 mole of sodium = 23 g.

Thus,

23 g of sodium contains 6.02×10²³ atoms.

Therefore, 4.5 g of sodium will contain = (4.5 × 6.02×10²³)/23 = 1.18×10²³ atoms.

From the above calculation,

4.5 g of sodium contains 1.18×10²³ atoms.

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3 years ago
1 point<br> How many moles of CO2 are there in 100.0 grams of CO2?
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44.0095 you're welcome hope this helps

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3 years ago
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Convert 44 centimeters to meters.<br> A. 4 m<br> B. 4.4 m<br> C. 0.44 m<br> D. 0.044 m
Hoochie [10]
The answer is C. 0.44 m
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3 years ago
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Determine the acid dissociation constant for a 0.0250 M weak acid solution that has a pH of 2.37 . The equilibrium equation of i
Oksanka [162]

Answer:

For part (a): pHsol=2.22

Explanation:

I will show you how to solve part (a), so that you can use this example to solve part (b) on your own.

So, you're dealing with formic acid, HCOOH, a weak acid that does not dissociate completely in aqueous solution. This means that an equilibrium will be established between the unionized and ionized forms of the acid.

You can use an ICE table and the initial concentration ofthe acid to determine the concentrations of the conjugate base and of the hydronium ions tha are produced when the acid ionizes

HCOOH(aq]+H2O(l]⇌ HCOO−(aq] + H3O+(aq]

I 0.20 0 0

C (−x) (+x) (+x)

E (0.20−x) x x

You need to use the acid's pKa to determine its acid dissociation constant, Ka, which is equal to

3 0
2 years ago
The electron configuration filling patterns of some elements in group 6b(6) and group 1b(11) reflect the ______ of half-filled a
Fudgin [204]

The electron configuration filling patterns of some elements in group 6b(6) and group 1b(11) reflect the increasing stability of half-filled and completely filled sublevels.

<h2>What is electronic configuration?</h2>

The distribution of electrons in an element's atomic orbitals is described by the element's electron configuration. Atomic subshells that contain electrons are placed in a series, and the number of electrons that each one of them holds is indicated in superscript for all atomic electron configurations. For instance, sodium's electron configuration is 1s22s22p63s1.

Almost all of the elements write their electronic configurations in the same style. When the energies of two subshells differ, an electron from the lower energy subshell occasionally goes to the higher energy subshell.

This is due to two factors:

Symmetrical distribution: As is well known, stability is a result of symmetry. Because of the symmetrical distribution of electrons, orbitals where the sub-shell is exactly half-full or totally filled are more stable.

Energy exchange: The electrons in degenerate orbitals have a parallel spin and are prone to shifting positions. The energy released during this process is simply referred to as exchange energy. The greatest number of exchanges occurs when the orbitals are half- or fully-filled. Its stability is therefore at its highest.

To know more about electronic configuration, go to URL

brainly.com/question/26084288

#SPJ4

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