3 years ago

Add me if you wanna be friends ( GIRLS ONLY p.s I’m a girl )

Chemistry

2 answers:

IgorC [24]3 years ago

7 0

Answer:

Hey there.

Explanation:

Have a nice day

tester [92]3 years ago

5 0

Answer:

YASSSSSS GIRLIESSSSS

Explanation:

You might be interested in

Foods that contain ___ should be prepared last. Allergens Citrus Nuts Apples

vladimir1956 [14]

Food that contains nuts should be prepared last

5 0

4 years ago

Which is a diatomic molecule? A. He B. O2 C. NaCl D. CuF2

katrin2010 [14]

O2 is the right answer

4 0

4 years ago

Read 2 more answers

2.303 3-5.05x10-3 1 | - 1 T2298

bekas [8.4K]

Answer:

230,294.9 I think it's fine just try your past or ask teacher help

6 0

3 years ago

Exercise A mixture of 250 mL of methane, CH4, at 35 °C and 0.55 atm and 750 mL of propane, C3Hg, at 35° C and 1.5 atm, were intr

dalvyx [7]

Explanation:

The given data is as follows.

$V_{1}$ = 250 mL, $V_{2}$ = 750 mL

$T_{1}$ = $35^{o}C$ = 35 + 273 K = 308 K

$T_{2}$ = 35 + 273 K = 308 K

$P_{1}$ = 0.55 atm, $P_{2}$ = 1.5 atm

P = ? , V = 10.0 L

Since, temperature is constant.

So, $P_{1}V_{1} + P_{2}V_{2}$ = PV

Now, putting the given values into the above formula as follows.

$P_{1}V_{1} + P_{2}V_{2}$ = PV

$0.55 atm \times 250 mL + 1.5 atm \times 1.5 atm$ = $P \times 10.0 L$

P = 0.126 atm

As, 1 atm = 760 torr. So, $0.126 atm \times \frac{760 torr}{1 atm}$ = 95.76 torr.

Thus, we can conclude that the final pressure, in torr, of the mixture is 95.76 torr.

8 0

3 years ago

The combustion of 14 grams of co according to the reaction co(g) ½o2(g) co2(g) 67.6 kcal gives off how much heat?

Irina18 [472]

The balanced reaction that describes the reaction between carbon monoxide and oxygen to produce carbon dioxide is expressed co(g)+ ½o2(g) → co2(g). The heat of combustion is 67.6 kcal per mole CO. We are given with 14 grams CO. Convert this to mole equal to 0.5 mole. Hence the total heat is 33.8 kcal.

3 0

4 years ago