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just olya [345]
3 years ago
9

1. A mutation is capable of reducing the amount of chlorophyll in the leaf. Would this also reduce the rate of photosynthesis?

Biology
1 answer:
Alex17521 [72]3 years ago
5 0

Answer:

No.This is because the amount of the chlorophyll; ls not a limiting factor of photosynthesis.

Explanation:

Generally the three factors are regarded as the limiting factors of photosynthesis.These are the CO2 concentration,light intensity,and temperature.Fluctuations in the availability of these factors affects the rate of photosynthesis.

When the rate of a chemical reaction depends on  a lot of reactions for its progress.The rate of this reaction is determined or  limited by the slowest in the reactions. This series of reactions govern this chemical reactions are the limiting factors. The one that is slowing down the rate of the reaction is said to limit it.

in the case of photosynthesis,  a decrease in the amount of CO2,but no change in the amount of other factors would affect the rate of photosynthesis. This is applicable to other factors fluctuation too ,which limits  the rate of photosynthesis

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B

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Rate will increase due to the decreation of the size

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This subatomic particle maintains a neutral charge.
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In mice, apricot eyes is recessive to black eyes. Tail length is governed by another gene, linked to the eye color gene. Long ta
just olya [345]

Answer:

trans

Explanation:

From the given information:

The study observes the genes present in mice for eye color and tail length. Since both genes are linked, it implies that they exist in the same chromosomes.

Black eyes is dominant over apricot eyes

Let Black eye be B and apricot eyes be b

Long tail is dominant over short tail

Let long tail be L and short tail be l

If double heterozygote(homoozygous-recessive) engage in the testcross

Then:

From the result given:

The parental combinations are:

Apricot eyes, Longtail  (bL / bl) =  33

Black eyes, Short tails (Bl / bl) = 30

The recombinant genes are:

Black eyes, Long tails (BL / bl) =  17

Apricot eyes, Short tails (bl / bl) = 20

The recombination frequency relates to the distance between the two genes which can be computed as:

= (20+17)/100

= 37%

Thus; the heterozygous parent is in trans arrangement.

8 0
3 years ago
nhóm nguy cơ sinh vật, phương pháp phòng tránh phát tán vi sinh vật và cách xử lí khi bị phơi nhiễm với vi sinh vật trong phòng
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Answer:

Washing hands daily and wear clean clothes.

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