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Marrrta [24]
3 years ago
12

Use the following equation to answer the question below:

Chemistry
1 answer:
Oduvanchick [21]3 years ago
3 0
<span>1) Balanced chemical equation

Sb2S3(s) + 3Fe(s) --> 2Sb(s) + 3FeS(s)

2) Theoretical molar ratios

1 mol SbsS3 : 3 mol Fe : 2 mol Sb : 3 mol FeS

3) Convert </span><span>18.45g Sb2S3 and12.1g Sb to moles

You need to use the atomic and molar masses

Sb: 121.76 g/mol

S: 32.07 g/mol

Sb2S3: 2 * 121.76 g/mol + 3 * 32.07 g/mol = 339.73 g/mol

18.45 g Sb2S3 / 339.73 g/mol = 0.0543 mol Sb2S3

12.1 g Sb / 121.76 g / mol = 0.099 mol Sb

Theoretical yield:

1 mol Sb2S3 / 2 mol Sb = 0.0543 mol SbsS3 / x mol Sb

Solve for x:

x = 0.0543 mol Sb2S3 * 2 mol Sb / 1 mol Sb2S3 = 0.1086 mol Sb

4) Percent yield

0.099 mol Sb / 0.1086 mol Sb * 100 = 91.16%

Answer: 91.5% (the difference with 91.16% is due to the decimals used for the atomic masses)
</span>
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Answer:

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6 0
3 years ago
Explain why the addition of a catalyst can make a reaction occur that doesn't normally occur at room temperature even when AG&lt
statuscvo [17]

A catalyst can cause a reaction to occur that does not normally happen at room temperature by reducing the activation energy needed to undergo the reaction.

<h3>What is a catalyst?</h3>

Catalysts are substances, often enzymes, used to speed up or commence a chemical reaction. They do this by reducing the necessary energy amount needed to begin the reaction, known as activation energy, or simply by changing the way in which the reaction takes place, which can allow for a reaction to take place even at <u>room temperature </u>when it would otherwise not occur.  

Therefore, we can confirm that a catalyst can cause a reaction to occur that does not normally happen at room temperature by reducing the activation energy needed to undergo the reaction.

To learn more about catalysts visit:

brainly.com/question/12260131?referrer=searchResults

6 0
2 years ago
There are five objects (a pink object, a yellow object, a white object, a gray object, and a violet object). Each object has a d
Serggg [28]
I- what is wrong with teachers???
3 0
3 years ago
Liquid octane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 17. g of octane is mi
Lisa [10]

Answer: 52.8 g of CO_2

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of octane

\text{Number of moles}=\frac{17.0g}{114g/mol}=0.150moles

b) moles of oxygen

\text{Number of moles}=\frac{93.0g}{32g/mol}=2.91moles

2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O

According to stoichiometry :

2 moles of C_8H_{18} require 25 moles of O_2

Thus 0.150 moles of  C_8H_{18} require=\frac{25}{2}\times 0.150=1.875moles  of O_2

Thus C_8H_{18} is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

As 2 moles of C_8H_{18} give =  16 moles of CO_2

Thus 0.150 moles of C_8H_{18} give =\frac{16}{2}\times 0.150=1.2moles  of CO_2

Mass of CO_2=moles\times {\text {Molar mass}}=1.2moles\times 44g/mol=52.8g

Thus 52.8 g of CO_2 will be produced from the given masses of both reactants.

8 0
3 years ago
Given that the concentration of myosin is 25pmol·L−1 and Rmax(Vmax)=208pmol·L−1·s−1 , determine the turnover number of the enzym
DedPeter [7]

Answer:

8.32 s⁻¹

Explanation:

Given that:

The concentration of myosin = 25 pmol/L

R_max = 208 pmol/L/s

The objective is to determine the  turnover number of the enzyme molecule myosin, which has a single active site.

In a single active site of enzyme is known to be a region where there is binding of between substrate molecules, thereafter undergoing chemical reaction.

The turnover number of the enzyme is said to be the number of these substrate molecule which binds together are being converted into products.

The turnover number of the enzyme molecule of myosin can be calculated by the expression: \dfrac{R_{max}}{concentration}

⇒ \dfrac{208 pmol/L/s}{25 pmol/L}

= 8.32 s⁻¹

4 0
4 years ago
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