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3 years ago

What is the partial pressure of C? atm C

Chemistry

1 answer:

s344n2d4d5 [400]3 years ago

8 0

The partial pressure of carbon is 45 mm Hg.

Explanation:

The partial pressure of carbon dioxide is referred as the amount of carbon dioxide present in venous or arterial blood. It acts as a ventilation in the lungs.
There is a formula for measuring partial pressure . As we know total pressure means summation of the pressure of all the gases included .
To find partial pressure we need- total pressure* fraction of mole of that gas. The partial pressure of CO2 is more because it carries deoxygenated blood from the whole body towards the lungs.

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A civil engineering student is considering buying an electric car. However, the conscious student wants to make sure her carbon

svetlana [45]

Answer:

$\text{An gasoline-powered vehicle has }\\\boxed{\text{five times the carbon footprint}}\text{ of an electric vehicle.}$

Explanation:

1. Miles travelled in an average month

$\text{Miles} = \text{1 mo} \times \dfrac{\text{52 wk}}{\text{12 mo}} \times \dfrac{\text{5 da}}{\text{1 wk}} \times \dfrac{\text{16 mi}}{\text{1 da}} = \text{347 mi}$

2. Using a gasoline powered vehicle

(a) Moles of heptane used

$n = \text{347 mi} \times \dfrac{\text{1 gal}}{\text{36.5 mi}}\times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{679.5 g}}{\text{1L}} \times \dfrac{ \text{1 mol}}{\text{100.20 g}}= \text{244 mol}$

(b) Equation for combustion

C₇H₁₆ + O₂ ⟶ 7CO₂ + 8H₂O

(c) Moles of CO₂ formed

$n = \text{244 mol heptane} \times \dfrac{\text{7 mol CO$_{2}$}}{\text{1 mol heptane}} = \text{1710 mol CO$_{2}$}$

(d) Volume of CO₂ formed

At 20 °C and 1 atm, the molar volume of a gas is 24.0 L.

$V = \text{1710 mol } \times \dfrac{\text{24.0 L}}{\text{1 mol}} \times \dfrac{\text{1 gal}}{\text{3.785 L}} = \textbf{10 800 gal}$

3. Using an electric vehicle

(a) Theoretical energy used

$\text{Theor. Energy} = \text{347 mi} \times \dfrac{\text{1 kWh}}{\text{5.2 mi}} = \text{66.7 kWh theor.}$

(b) Actual energy used

The power station is only 85 % efficient.

$\text{Actual energy used} = \text{66.7 kWh theor.} \times \dfrac{\text{100 kWh actual}}{\text{ 85 kWh theor.}}\times \dfrac{\text{3600 kJ}}{\text{1 kWh}}\\\\ = 2.82\times 10^{5} \text{ kJ}\$

(c) Combustion of CH₄

CH₄ + 2O₂ ⟶ CO₂ +2 H₂O

(d) Equivalent volume of CO₂

The heat of combustion of methane is -802.3 kJ·mol⁻¹

$V= 2.82\times 10^{5}\text{ kJ} \times \dfrac{\text{1 mol methane}}{\text{802.3 kJ}} \times \dfrac{\text{1 mol CO$_{2}$} }{\text{1 mol methane}} \times \dfrac{ \text{24.0 L}}{ \text{1 mol CO$_{2}$}}\\\\ \times \dfrac{\text{1 gal}}{\text{3.875 L}} = \textbf{2180 gal}$

4. Comparison

$\dfrac{V_{\text{gasoline}}}{V_{\text{electric}}} = \dfrac{10800}{2180} = 5.0\\\\ \text{An gasoline-powered vehicle has }\\ \boxed{\textbf{ five times the carbon footprint}}\text{ of an electric vehicle.}$

6 0

2 years ago

Pls help ty so much!

Nitella [24]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:mass = 11.42 \:\: grams$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: Q = ms\Delta T$

$\textsf{Q = heat evolved/absorbed = 501 J}$

$\textsf{m = mass in gram = ?}$

$\textsf{s = specific heat = 0.45}$

$\textsf{ΔT = change in temp = 120 - 22.5 =97.5°C}$

$\large\textsf{Find m : }$

$\qquad \tt \rightarrow \: 501 = m \sdot(0.45) \sdot(97.5)$

$\qquad \tt \rightarrow \: 501 = m \sdot43.875$

$\qquad \tt \rightarrow \: m = \dfrac{501}{43.875}$

$\qquad \tt \rightarrow \: m \approx11.42 \: \: g$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

4 0

1 year ago

What is the mass of alliminum?

Gennadij [26K]

Answer:

26.981539 u

Atomic number: 13

Symbol: Al

Electron configuration: [Ne] 3s²3p¹

5 0

2 years ago

Read 2 more answers

The bond dissociation energy to break 4 bond(s) in 1 mole of CH₄ molecules is:_____ **Any help would be greatly appreciated!**

frozen [14]

Answer:

The bond dissociation energy to break 4 bonds in 1 mol of CH is 1644 kJ

Explanation:

Since there are 4 C-H bonds in CH₄, the bond dissociation energy of 1 mol of CH₄ is 4 × bond dissociation energy of one C-H bond.

From the table one mole is C-H bond requires 411 kJ, that is 411 kJ/mol. Therefore, 4 C-H bonds would require 4 × 411 kJ = 1644 kJ

So, the bond dissociation energy to break 4 bonds in 1 mol of CH₄ is 1644 kJ

5 0

3 years ago

Glucose and hexanoic acid each contain six carbon atoms, but they have completely different properties. Glucose is a nutrient fo

Bogdan [553]

Answer:

Functional groups.

Explanation:

Functional groups are the specific substituents present within the molecules which are responsible for characteristic chemical properties the molecule shows.

Glucose contains alcohol and aldehyde group while hexanoic acid contains carboxylic acid group. <u>The presence different types of the functional groups in both the compounds results in the difference in the properties of both the compounds.</u>

3 0

2 years ago