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3 years ago

Which is the difference between proximal and distal positions?

2 answers:

8 0

Answer: These two terms are almost always used in reference to relative locations of parts or places on the limbs. Proximal then refers to something closer to the torso while distal refers to parts and places away from the torso. So a finger is distal to the wrist, which is distal to the elbow, which is distal to the shoulder

STatiana [176]3 years ago

4 0

Answer:

Proximal positions are those positions near the midline while distal positions are those positions far away from the midline.

The midline is that middle line intersecting sagittal, coronal, and transverse planes.

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The melting temperature of pure titanium = 1668°C, its density = 4.5 g/cm^3, specific heat = 0.544 J/gºC, and heat of fusion = 4

nataly862011 [7]

Answer:

A) 1384.6 J/g

b)110.768 MJ

Explanation:

Given data:

$T_{melting} = 1668 degree C$

density of titanium = 4.5 g/cm^3

specific heat = 0.544 J/g degree C

heat of fusion = 419 J/g

Pouring temperature for titanium = 1800 degree C

Initial temperature = 25 degree C

a) eneegy for heating unit mass is given as

$E = C(T_{melting} - T_{initial}) + L + C(T_{pouring} - T_{melting})$

$= 0.544(1668-25) + 419 + 0.544(1800-1668)$

= 1384.6 J/g

b) Total energy to heat 80 kg metal

we know for one unit 1384.6 J/g energy is required

therefore for 80 kg , energy required is

$E = (80\times 1000) 1384.6$

= 110768000 J

$= 110.768 \times 10^6 J$

5 0

3 years ago

What is Euler's equation?

igomit [66]

Answer:

$e^{ix} = cosx + i sinx$

Explanation:

In mathematics, Euler's formula is an equation in complex analysis, that gives a relationship between an exponential factor and the trigonometric functions.

The Euler equation is:

$e^{ix} = cosx + i sinx$

Here,

e - base of the natural logarithm

i - imaginary unit

x - argument given in radians

sin , cos - trigonometric functions sine and cosine respectively.

4 0

4 years ago

If the bending moment (M) is 4,176 ft-lb and the beam is an 1 beam, calculate the bending stress (psi) developed at a point with

SpyIntel [72]

Answer:

Bending stress at point 3.96 is \sigma_b = 1.37 psi

Explanation:

Given data:

Bending Moment M is 4.176 ft-lb = 50.12 in- lb

moment of inertia I = 144 inc^4

y = 3.96 in

$\sigma_b = \frac{M}{I} \times y$

putting all value to get bending stress

$\sigma_b = \frac{50.112}{144} \times 3.96$

$\sigma_b = 1.37 psi$

Bending stress at point 3.96 is $\sigma_b$ = 1.37 psi

3 0

4 years ago

We need to design a logic circuit for interchanging two logic signals. The system has three inputs I1I1, I2I2, and SS as well as

Salsk061 [2.6K]

Explanation:

Inputs and Outputs:

There are 3 inputs = I₁, I₂, and S

There are 2 outputs = O₁ and O₂

The given problem is solved in three major steps:

Step 1: Construct the Truth Table

Step 2: Obtain the logic equations using Karnaugh map

Step 3: Draw the logic circuit

Step 1: Construct the Truth Table

The given logic is

When S = 0 then O₁ = I₁ and O₂ = I₂

When S = 1 then O₁ = I₂ and O₂ = I₁

I₁ | I₂ | S | O₁ | O₂

0 | 0 | 0 | 0 | 0

0 | 0 | 1 | 0 | 0

0 | 1 | 0 | 0 | 1

0 | 1 | 1 | 1 | 0

1 | 0 | 0 | 1 | 0

1 | 0 | 1 | 0 | 1

1 | 1 | 0 | 1 | 1

1 | 1 | 1 | 1 | 1

Step 2: Obtain the logic equations using Karnaugh map

Please refer to the attached diagram where Karnaugh map is set up.

The minimal SOP representation for output O₁

$O_1 = I_1 \bar{S} + I_2 S$

The minimal SOP representation for output O₂

$O_2 = I_2 \bar{S} + I_1 S$

Step 3: Draw the logic circuit

Please refer to the attached diagram where the circuit has been drawn.

7 0

3 years ago

Consider a system whose temperature is 18°C. Express this temperature in R, K, and °F.

zvonat [6]

Answer:

In Rankine 524.07°R

In kelvin 291 K

In Fahrenheit 64.4°F

Explanation:

We have given temperature 18°C

We have to convert this into Rankine R

From Celsius to Rankine we know that $T(R)=(T_{C}+273.15)\frac{9}{5}$

We have to convert 18°C

So $T(R)=(18+273.15)\frac{9}{5}=524.07^{\circ}R$

Conversion from Celsius to kelvin

$T(K)=(T_{C}+273)$

We have to convert 18°C

$T(K)=(18+273)=291K$

Conversion of Celsius to Fahrenheit

$T(F)=T_{C}\times \frac{9}{5}+32=64.4^{\circ}F$

7 0

3 years ago

Which is the difference between proximal and distal positions?​

Which is the difference between proximal and distal positions?