Answer:
P= 5.5 bar
Explanation:
Given that
L= 4000 m
d= 0.2 m
Friction factor(F) = 0.01
speed V= 2 m/s
Head = 5 m
Head loss due to friction



So the total head(H) = 5 + 40.77 + 10.3 =56.07
Where 10.3 m is the atmospheric head.
We know that
P=ρ g H
So total Pressure
P= 1000 x 9.81 x 56.07 Pa

P= 5.5 bar
Answer:
1. Band saw lower wheel does not require a guard * true or false 2. Band saw upper guide should be adjusted to within 1/8" of the work piece * true or false 3. Find board & linear ft for 10 pieces of 4" x 4" x 8' *
<u>Explanation:</u>
Task 1 time period = 200ms, Task 2 time period = 300ms
Task ticked =
→ 5 times
Task 2 ticked =
→ 3 times
At 600 ms → 200ms 200ms 200ms
300ms → 
Largest time period = H.C.M of (200ms, 300ms)
= 600ms
Answer:
1st part: Section W18X76 is adequate
2nd part: Section W21X62 is adequate
Explanation:
See the attached file for the calculation
Answer:
T₂ =93.77 °C
Explanation:
Initial temperature ,T₁ =27°C= 273 +27 = 300 K
We know that
Absolute pressure = Gauge pressure + Atmospheric pressure
Initial pressure ,P₁ = 300+1=301 kPa
Final pressure ,P₂= 367+1 = 368 kPa
Lets take temperature=T₂
We know that ,If the volume of the gas is constant ,then we can say that


Now by putting the values in the above equation we get

The temperature in °C
T₂ = 366.77 - 273 °C
T₂ =93.77 °C