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3 years ago

An add tape of 101 ft is incorrectly recorded as 100 ft for a 200-ft distance. What is

Engineering

1 answer:

baherus [9]3 years ago

4 0

Answer:

the correct distance is 202 ft

Explanation:

The computation of the correct distance is shown below:

But before that correction to be applied should be determined

= (101 ft - 100 ft) ÷ (100 ft) × 200 ft

= 2 ft

Now the correct distance is

= 200 ft + 2 ft

= 202 ft

Hence, the correct distance is 202 ft

The same would be relevant and considered too

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Ammonia is one of the chemical constituents of industrial waste that must be removed in a treatment plant before the waste can s

Yanka [14]

Answer:

Following is attached the solution or the question given.

I hope it will help you a lot!

Explanation:

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3 years ago

Air is compressed slowly in a piston-cylinder assembly from an initial state where P1 = 1.4 bar, V1= 4.25 m^3, to a final state

lord [1]

Answer:

W=-940.36 KJ

Explanation:

Given that

$P_1=1\ bar,V_1=4.25 {m^3}$

$P_2=6.8\ bar$

Process follows pv=constant

So this is the isothermal process and work in isothermal process given as

$W=P_1V_1\ln \dfrac{P_1}{P_2}$

Now by putting the values (1.4 bar =140 KPa)

$W=P_1V_1\ln \dfrac{P_1}{P_2}$

$W=140\times 4.25 \ln \dfrac{1.4}{6.8}$

W=-940.36 KJ

Negative sign indicates that this is a compression process and work will given to the system.

7 0

4 years ago

A train travels 650 meters in 25 seconds. What is the train's velocity?

frosja888 [35]

The train is traveling 26 meters A second .

3 0

3 years ago

A balanced three-phase 208 V wye-connected source supplies a balanced three-phase wyeconnected load. If the line current IA is m

tatyana61 [14]

Answer:

6.004 Ω

Explanation:

For a Y- connected system given that :

Line voltage, $V_L = 208 \ V$

Line current , $I_L=20\ A$

and specified that $V_L \ and \ I_L$ are in phase.

Hence the impedance will be pure resistive.

For Y-system

$V_L = \sqrt3 V_{ph}$

$V_{ph}$ = phase voltage

$V_{ph}$ $=\frac{V_L}{\sqrt3} = \frac{208}{\sqrt3}$

= 120.08 V

Line current = Phase current

$I_L = I_{ph} = 20 \ A$

Now, $z_{ph} = \frac{V_{ph}}{I_{ph}}=\frac{120.08}{20}$

= 6.004 Ω

5 0

3 years ago

. A normal-weight concrete has an average compressive strength of 20 MPa. What is the estimated flexure strength

bulgar [2K]

Answer:

2.77mpa

Explanation:

compressive strength = 20 MPa. We are to find the estimated flexure strength

We calculate the estimated flexural strength R as

R = 0.62√fc

Where fc is the compressive strength and it is in Mpa

When we substitute 20 for gc

Flexure strength is

0.62x√20

= 0.62x4.472

= 2.77Mpa

The estimated flexure strength is therefore 2.77Mpa

4 0

3 years ago