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Alja [10]
3 years ago
12

A segment of a roadway has a free flow speed of 45 mph and a jam density of 25 ft per vehicle. Determine the maximum flow and at

a flow rate of 1950 vph
Engineering
1 answer:
-BARSIC- [3]3 years ago
4 0

Answer:

2376 vph

Explanation:

Given data

free flow speed ( Vf ) = 45 mph

Jam density = 25 ft per vehicle

flow rate = 1950 vph

first we calculate the Jam density in vehicle /mile

= 5280 / 25 = 211.2 vehicle/mile

where ; 1 mile = 5280 feet

The maximum flow can be calculated using Greenshield method

q = ( Vf * jam density ) / 4  =  ( 45 * 211.2 ) / 4

  = 2376 vph

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3 years ago
A pipeline (NPS = 14 in; schedule = 80) has a length of 200 m. Water (15℃) is flowing at 0.16 m3/s. What is the pipe head loss f
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Answer:

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Explanation:

Given data:

Length (L) = 200 m

Discharge (Q) = 0.16 m3/s

According to table of nominal pipe size , for schedule 80 , NPS 14,  pipe has diameter (D)= 12.5 in or 31.8 cm 0.318 m

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where, f = Darcy friction factor

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g = acceleration due to gravity

We know, flow rate Q = A x V

solving for V

V = \frac{Q}{A}

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For Schedule 80 PVC pipes , roughness (e) is  0.0015 mm

Relative roughness (e/D) = 0.0015 / 318 = 0.00005

from Moody diagram, for Re = 640000 and e/D = 0.00005 , Darcy friction factor , f = 0.0126

Therefore head loss is

HL = \frac{0.0126 (200)(2.015)^2}{( 2 \times 9.81 \times 0.318)}

HL = 1.64 m

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4 years ago
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