Answer:
C
Step-by-step explanation:
Answer: The nth term of a geometric progression is Tn = ar^(n-1)
A. 12
B. 3.6
C. -3/4
D. 0.6
Step-by-step explanation:
The nth term of a geometric progression is Tn = ar^(n-1)
Where Tn= nth term
a = first term
r = common ratio
n = number
A. a6 = (2*6) = 12
B. a6 = (0.6*6) = 3.6
C. a6 = (-1/8*6) = -3/4
D. a6 = (0.1*6) = 0.6
Answer:
144 ways
Step-by-step explanation:
Number of paintings = 7
Renaissance = 4
Baroque = 3
We are hanging from left to right and we will first hang Renaissance painting before baroque painting.
For Renaissance we have 4! Ways of doing so. 4 x3x2x1 = 24
For baroque we have 3! Ways of doing so. 3x2x1 = 6
We have 4!ways x 3!ways
= (4x3x2x1) * (3x2x1) ways
= 144 ways
Therefore we have 144 ways to hang the painting.
Answer:
Part 1) Option D. must be an acute angle
Part 2) m∠A=70°
Step-by-step explanation:
Part 1) In triangle ABC, if an exterior angle drawn at vertex C measures 45, then angle B...
we know that
An exterior angle of a triangle is equal to the sum of the opposite interior angles
so
The measure of an exterior angle at C is equal to the sum of the interior angles at A and B
we have that
45°=m∠A+m∠B
therefore
m∠B < 90°
Angle B must be an acute angle
Part 2)
we know that
An exterior angle of a triangle is equal to the sum of the opposite interior angles
so
The measure of an exterior angle at B is equal to the sum of the interior angles at A and C
m∠A+m∠C=2m∠C+5
m∠C=m∠A-5 ----> equation A
m∠C=65° ----> equation B
substitute equation B in equation A
65°=m∠A-5
m∠A=(65+5)°=70°
Answer:
0
Step-by-step explanation:
so p can be larger than -12 or can be -12
so the only answer there is 0
