Answer:
C₂ = 1.26 mol/dm³
Explanation:
Given data:
Volume of HCl =V₁ = 15.7 cm³
Volume of LiOH = V₂ = 25 cm³
Concentration of HCl =C₁ = 2 mol/dm³
Concentration of LiOH =C₂= ?
Solution:
Chemical equation:
LiOH + HCl → LiCl + H₂O
Formula:
C₁V₁ = C₂V₂
by putting values,
15.7 cm₃× 2 mol/dm³ = C₂× 25 cm³
C₂ = 15.7 cm₃× 2 mol/dm³ / 25 cm³
C₂ = 31.4 cm₃.mol/dm³ / 25 cm³
C₂ = 1.26 mol/dm³
Prior to writing the chemical formula of magnesium chloride, a question which any student will need to ask is: A. What are the oxidation numbers of each atom?
A chemical formula can be defined as a scientific notation that is used to show (represent) the type and total number of atoms that constitute a particular chemical molecule or compound, by using the oxidation number, chemical symbols and subscripts.
Hence, a student would need to know the oxidation numbers of each atom when magnesium chloride is formed after a chemical reaction.
In Chemistry, an oxidation number represents the number of electrons <u>gained</u> or <u>lost</u> by an atom of a chemical element during a chemical reaction.
In conclusion, when magnesium chloride is formed, a question which the student will need to ask prior to writing the chemical formula is "what are the oxidation numbers of each atom?"
Read more: brainly.com/question/13750908
Answer:
c. 2 and 3
Explanation:
Ca(NO3)2 names calcium nitrate.
Ca metal, O, N - nonmetals, so Ca(NO3)2 is ionic compound.
It is solid and white.
Given :
Number of moles of CHF₃ is 1.7 .
Solution :
We know, 1 mole of any complex contains 6.022 × 10²³ molecules.
Let, 1.7 moles of CHF₃ contains n numbers of molecules.
So, n = 1.7 × 6.022 × 10²³ molecules
n = 10.2374 × 10²³ molecules
n = 1.0237 × 10²³ molecules
Hence, this is the required solution.
Hey there!
<span>Use the equation of Clapeyron:
</span>
T in kelvin :
26 + 273.15 => 299.15 K
R = 0.082
V = 10.2 L
P = 0.98 atm
number of moles :
P *V = n * R * T
0.98 * 10.2 = n * 0.082 * 299.15
9.996 = n * 24.5303
n = 9.996 / 24.5303
n = 0.4074 moles
Therefore:
Molar mass H2O = 18.01 g/mol
1 mole H2O ------------- 18.01 g
0.4074 moles ----------- m
m = 0.4074 * 18.01 / 1
m = 7.339 g of H2O
