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zmey [24]
3 years ago
13

Study the force diagram to complete the sentences. The forces acting on the box are . The box will move to the .

Physics
2 answers:
Oduvanchick [21]3 years ago
8 0

unbalanced and right

Viktor [21]3 years ago
5 0

Answer: unbalanced and right

Explanation:

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While the water falls v increases and h decreases, so the kinetic energy increases and the gravitational potential energy decreases, and this happens in a way that the total energy is always the same. (If there is no friction)

Explanation:

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The bar graph shows energy data taken from a roller coaster at a theme park. analyze the data and assess its validity. 3-5 sente
hichkok12 [17]

This question involves the concepts of the law of conservation of energy, potential energy, and kinetic energy.

The data shown by the bar graph is "valid".

According to the law of conservation of energy, the total energy of the system must remain constant at any given point. Hence, the sum of the kinetic energy and the potential energy of the roller coaster must be constant at any given time.

Considering the bottom of the first hill:

Total Energy at 1st Hill = Kinetic Energy + Potential Energy

From the data given in the bar graph:

Total Energy at 1st Hill = 2,500,000 J + 0 J (since at the bottom potential energy is zero due to zero height)

Total Energy at 1st Hill = 2,500,000 J

Now, considering the top of the second hill:

Total Energy at 2nd Hill = Kinetic Energy + Potential Energy

From the data given in the bar graph:

Total Energy at 2nd Hill = 1,000,000 J + 1,500,000 J

Total Energy at 2nd Hill = 2,500,000 J

Hence,

Total Energy at 1st Hill = Total Energy at 2nd Hill

Therefore, the given bar graph is "valid".

Learn more about the law of conservation of energy here:

brainly.com/question/20971995?referrer=searchResults

The attached picture explains the law of conservation of energy.

4 0
2 years ago
A car is driving along a road at a speed of 50 km/hr. How far will the car travel in 5 hours?​
BARSIC [14]

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I think it's 250

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4 0
2 years ago
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