Candle is the correct answer to the answer
Answer:
a. V = 0.015 m³
b. ζ = 195.58 kg acetone / hr
Explanation:
a.
Assume ideal gas behavior can use the equation
n₁ = 1.1 bar / 1.013 bar = 1.085 * 1m³( 273 k / 478 k ) * ( 1 kmol / 274 m³)
n₁ = 0.0276 kmol
Pacetone = 0.1 bar ⇒ y₁ = 0.1 bar / 1.1 bar
y₁ = 0.09090
Pacetone = 0.379 bar ⇒ y₃ = 0.379 bar / 40 bar
y₃ = 9.475 x10 ⁻³
n₁ * y₁ = n₃ * y₃ ⇒ 0.0276 * ( 1 - 0.09090) = n₃ * ( 1 - 9.475 x 10⁻³)
n₃ = 0.0253 kmol
n₁ = n₂ + n₃ ⇒ n₂ = 0.0276 - 0.0253 = 2.30 x 10 ⁻³ kmol
Volume condesed
V = 0.0253 kmol * 22.4 m³ * ( 283 / 273 ) * ( 1013 bar / 40 bar )
V = 0.015 m³
b.
To calculate the rate vaporized
ζ = 20.0 m³ / hr *( 0.0276 / 0.014 kg * m³ ) *( 0.09090 kmol a / kmol ) * ( 5808 kg a / kmol a )
ζ = 195.58 kg acetone / hr
Hope u r fine user
During this pandemic
I think it depends on a objects weight
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Answer:
Explanation:
One of the consecuences of Special Theory of Relativity is that when bodies move its length in the direction of the movement will decrease, and decrease will become bigger as speed goes up. At speed close to speed of light such decrease could be such as to make train become a point, of course tunnel is fixed it will not change, but close to light speed means somethyng like 300000 km/sec therefore could be just one instant of time inside tunnel no matter how long it is