The elastic potential energy increases by a factor of 9
Explanation:
The elastic potential energy of a bowstring is given by
(1)
where
k is the spring constant
x is the elongation of the bowstring
Hooke's law states the relationship between the force applied and the elongation of an elastic object:

where
F is the force applied
x is the elongation
We can rewrite it as

And substituting into (1),

In this problem, the force applied to the bowstring is tripled,
F' = 3F
So the final elastic potential energy is:

So, the elastic potential energy increases by a factor of 9.
Learn more about potential energy:
brainly.com/question/1198647
brainly.com/question/10770261
#LearnwithBrainly
The changes in internal energy of the system <u>75.1 J.</u>
The internal energy of a thermodynamic system is the total energy contained in it. It is the energy required to create or prepare a system in a given internal state and includes contributions of potential energy and internal kinetic energy.
Calculation:
Internal energy = 162.4 j - work done
= 162.4 j - 87.3 j
=<u> 75.1 J</u>
<u />
Internal energy, in thermodynamics, is the property or state function that defines the energy of matter in the absence of capillary action or external electric, magnetic, or other fields.
Internal energy is the microscopic energy contained in the matter given by the random and disordered kinetic energy of the molecules. It also includes the potential energy between these molecules and the nuclear energy contained in the atoms of these molecules.
Learn more about internal energy here:-brainly.com/question/15735187
#SPJ4
Answer:
a) a = 6.1 m/s^2
b) a = 0.98m/s^2
Explanation:
Mass of slab = 40kg
Mass of block = 10kg
Coefficient of static friction (Us) = 0.60
Kinetic coefficient (UK) = 0.40
Horizontal force = 100N
The normal reaction from 40kg slab on 10 kg block = 10*9.81
= 98.1N
Static frictional force = Us*R
= 98.1*0.6
= 58.86N
This is less than the force applied
If 10 kg block will slide on the 40 kg slab, net force = 100 - kinetic force
Kinetic force (Uk*R) = 0.4*98.1
= 39.28N
= 39N
Net force = 100 -39
= 61N
Recall that F = ma
For 10 kg block
a = F/m
a = 61/10
a = 6.1m/s^2
b) Frictional force on 40 kg slab by 10 kg = 98.1*0.4
= 39.24
= 39N
F = ma
a = F/m
For 40kg slab
a = 39/40
a = 0.98m/s^2
As for me, the reson why scientists usually write reports about their investigations is because they want to <span>d. to communicate their work to other scientist. As far as I am concerned in this sphere they have to get many other opnions besides their own in order to complete or expand one that they have made up. Hope it helps :)</span>
Answer:
d = 5.10 m
Explanation:
As we know that here on the plane of the inclined there is no frictional force
So in these cases we can say that total mechanical energy will always remains conserved
so here we can say that
spring potential energy = gravitational potential energy of the block
as we know from the formula

now plug in the values in it



now as we know that the angle of inclination is 60 degree and height raised is 4.42 m
so here maximum distance moved along the inclined plane will be


