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JulijaS [17]
3 years ago
6

COURCES

Physics
1 answer:
lutik1710 [3]3 years ago
7 0

Answer:

13.0186g/mole

63.0326g/mole

Explanation:

Given parameters;

Compounds - CH

                       CH₃O₃

To solve this problem, let us delve a bit into molar mass of a substance;

The molar mass of a substance (atom or molecule or compound) is the mass in grams of one mole of the substance.

Simply add the component atomic masses to find this number;

Atomic mass of Carbon = 12.0107g/mole

                          Hydrogen  = 1.0079g/mole

                          Oxygen    = 15.9994g/mole

Molar mass of CH  = 12.0107 + 1.0079 = 13.0186g/mole

Molar mass of   CH₃O₃ = 12.0107 + 3(1.0079) + 3( 15.9994) = 63.0326g/mole

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Answer:

V_3\approx 4.28\,\,V

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Explanation:

Notice that this is a circuit with resistors R1 and R2 in parallel, connected to resistor R3 in series. It is what is called a parallel-series combination.

So we first find the equivalent resistance for the two resistors in parallel:

\frac{1}{Re}= \frac{1}{R1}+\frac{1}{R2}\\\frac{1}{Re}= \frac{1}{100}+\frac{1}{50}\\\frac{1}{Re}= \frac{3}{100}\\Re=\frac{100}{3} \,\,\Omega

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Vs=I\,*\,(\frac{100}{3} +25)\\10=I\,*\,\frac{175}{3} \\I=\frac{30}{175} \,amps

So approximately 0.17  amps

and therefore, we can estimate the voltage drop (V3) in R3 uisng Ohm's law:

V_3=\frac{30}{175} *\,25=\frac{30}{7} \approx 4.28\,\,V

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10 V -  4.28 V = 5.72 V

and with this info, we can calculate the current through R1 using Ohm's Law:

I_1=\frac{V_1}{R_1} =\frac{5.72}{100} =0.0572\,\,amps

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<h2>Answer:</h2>

<h3>b. E</h3>

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