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JulijaS [17]
3 years ago
6

COURCES

Physics
1 answer:
lutik1710 [3]3 years ago
7 0

Answer:

13.0186g/mole

63.0326g/mole

Explanation:

Given parameters;

Compounds - CH

                       CH₃O₃

To solve this problem, let us delve a bit into molar mass of a substance;

The molar mass of a substance (atom or molecule or compound) is the mass in grams of one mole of the substance.

Simply add the component atomic masses to find this number;

Atomic mass of Carbon = 12.0107g/mole

                          Hydrogen  = 1.0079g/mole

                          Oxygen    = 15.9994g/mole

Molar mass of CH  = 12.0107 + 1.0079 = 13.0186g/mole

Molar mass of   CH₃O₃ = 12.0107 + 3(1.0079) + 3( 15.9994) = 63.0326g/mole

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IgorC [24]

When conducting and experiment you want to have a notebook and something to write down notes with so you can keep everything organized and proper, and to not miss anything in the experiment. Also you want to have everything in order of the way it should be in.

I hope you found this helpful!

5 0
3 years ago
URGENT HELP<br> WILL GIVE U BRAINLIEST
katrin [286]

Answer:

<h3><u>1</u><u>2</u><u>9</u><u> </u><u>N</u></h3>

Explanation:

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7 0
3 years ago
The wheel of a car has a radius of 20.0 cm. It initially rotates at 120 rpm. In the next minute it makes 90.0 revolutions. (a) W
just olya [345]

Answer:

Explanation:

Given that,

Radius of the wheel, r = 20 cm = 0.2 m

Initial speed of the wheel, \omega_i=120\ rpm=753.98\ rad/s

Displacement, \theta=90\ rev=565.48\ rad

To find,

The angular acceleration and the distance covered by the car.

Solution,

Let \alpha is the angular acceleration of the car. Using equation of rotational kinematics as :

\theta=\omega_i t+\dfrac{1}{2}\alpha t^2

565.48=753.98\times 60+\dfrac{1}{2}\alpha (60)^2

\alpha =-24.81\ rad/s^2

Let t is the time taken by the car before coming to rest.

t=\dfrac{\omega_f-\omega_i}{\alpha }

t=\dfrac{0-753.98}{-24.81}

t = 30.39 seconds

Let v is the linear velocity of the car. So,

v=r\times \omega_i

v=0.2\times 753.98

v = 150.79 m/s

Let d is the distance covered by the car. It can be calculated as :

d=v\times t

d=150.79\ m/s\times 30.39\ s

d = 4582.5 meters

or

d = 4.58 km

5 0
3 years ago
A ball is thrown vertically upward, which is the positive direction. A little later, it returns to its point of release. The bal
Aleks [24]

Answer:

The initial velocity of the ball is <u>39.2 m/s in the upward direction.</u>

Explanation:

Given:

Upward direction is positive. So, downward direction is negative.

Tota time the ball remains in air (t) = 8.0 s

Net displacement of the ball (S) = Final position - Initial position = 0 m

Acceleration of the ball is due to gravity. So, a=g=-9.8\ m/s^2(Acting down)

Now, let the initial velocity be 'u' m/s.

From Newton's equation of motion, we have:

S=ut+\frac{1}{2}at^2

Plug in the given values and solve for 'u'. This gives,

0=8u-0.5\times 9.8\times 8^2\\\\8u=4.9\times 64\\\\u=\frac{4.9\times 64}{8}\\\\u=4.9\times 8=39.2\ m/s

Therefore, the initial velocity of the ball is 39.2 m/s in the upward direction.

3 0
4 years ago
...........................
Ugo [173]

Answer: kooi kooi

how r u and thanks for the free points :)

8 0
3 years ago
Read 2 more answers
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