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expeople1 [14]
2 years ago
8

Because weight is a measurement of the amount of gravity pulling on an object, weight is considered a ______. Question 18 option

s: gravity force velocity motion.
Physics
1 answer:
Andrews [41]2 years ago
6 0

Answer: Force I believe.

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A pulley is most closely related to which simple machine?
MrRissso [65]

Answer: wheel and axle

Explanation:

5 0
3 years ago
Read 2 more answers
What is a microwave?
bonufazy [111]

Answer:

an electromagnetic wave with a wavelength in the range 0.001–0.3 m, shorter than that of a normal radio wave but longer than those of infrared radiation. Microwaves are used in radar, in communications, and for heating in microwave ovens and in various industrial processes.

7 0
3 years ago
You toss a bowling ball straight up into the air with a speed of 2.1 m/s. How long does it take the bowling ball to reach its hi
lara [203]

Time taken by the bowling ball to reach its highest point= 0.214 s

initial velocity= Vi=2.1 m/s

Final velocity= Vf=0 as the velocity at the highest point is zero.

acceleration= g= -9.8 m/s²

using the kinematic equation Vf= Vi + at

0= 2.1 + (-9.8)t

t= -2.1/-9.8

t=0.214 s

Thus the time taken by the bowling ball to reach its highest point is 0.214 s

6 0
3 years ago
Capacitor 2 has half the capacitance and twice the potential difference as capacitor 1. What is the ratio (U_{\rm C})_1/\,(U_{\r
IrinaK [193]

Answer:

1/2

Explanation:

The energy stored in a capacitor is given by

U=\frac{1}{2}CV^2

where

C is the capacitance

V is the potential difference

Calling C_1 the capacitance of capacitor 1 and V_1 its potential difference, the energy stored in capacitor 1 is

U=\frac{1}{2}C_1 V_1^2

For capacitor 2, we have:

- The capacitance is half that of capacitor 1: C_2 = \frac{C_1}{2}

- The voltage is twice the voltage of capacitor 1: V_2 = 2 V_1

so the energy stored in capacitor 2 is

U_2 = \frac{1}{2}C_2 V_2^2 = \frac{1}{2}\frac{C_1}{2}(2V_1)^2 = C_1 V_1^2

So the ratio between the two energies is

\frac{U_1}{U_2}=\frac{\frac{1}{2}C_1 V_1^2}{C_1 V_1^2}=\frac{1}{2}

4 0
3 years ago
What force is required to move an object 8 m using 24 j of work?
Anna35 [415]

Answer:

3N

Explanation:

Workdone = F x d

F = force

d = distance 8m

Workdone = 24J

24 = F x 8

Divide both sides by 8

24/8 = F x 8/8

3 = F

F = 3N

7 0
3 years ago
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