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svet-max [94.6K]
4 years ago
9

Write the following proportion using colons. 7 is to 21 as 3 is to 9.

Mathematics
2 answers:
Lubov Fominskaja [6]4 years ago
7 0
The answer is 7:21 = 3:9.
Ksenya-84 [330]4 years ago
4 0

Answer:

Option A.

Step-by-step explanation:

There are two fraction given in this question and we have to write the proportion using colon.

Visually fractions \frac{7}{21} and \frac{3}{9} are different but when we simplify these fractions we get the actual relation between them.

We simplify \frac{7}{21} first.

By dividing from 7 in the numerator and denominator we get

\frac{\frac{7}{7}}{\frac{21}{7}}=\frac{1}{3}

similarly we simplify the fraction \frac{3}{9}

By dividing numerator and denominator by 3

\frac{\frac{3}{3} }{\frac{9}{3} }=\frac{1}{3}

Now we can say that both the fractions are equal.

\frac{7}{21}=\frac{3}{9}=\frac{1}{3}

So the ratio will be 7 : 21 = 3 : 9

Option A. will be the answer.

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Amy is cooking pancakes. The recipe calls for 5 1/4 cups of milk. She already has put in 2 1/10 cups. How many more cups does sh
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Ok so lets break it down.

Step-by-step explanation:

5-2 = 3 now we have 1/4 and 1/10 10 divided by 4 = 2.5

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then we add them up equals 3.5 out of ten.

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3 years ago
Simplify 7-(x^2-3x+2)-2x(3x^2-x+1)
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Answer:

-6x^3+x^2+x+5

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distribute (multiply) the 7- into the first set of parenthesis. then distribute (multiply) the -2x into the second set of parenthesis.

3 0
3 years ago
Last year, a comprehensive report stated that 28% of businesses in the northeast of Ohio were considered highly profitable. This
Alik [6]

Answer:

z=\frac{0.38 -0.28}{\sqrt{\frac{0.28(1-0.28)}{50}}}=1.575  

p_v =2*P(z>1.575)=0.115  

So the p value obtained was a very high value and using the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of businesses were highly profitable is not significantly different from 0.28 or 28%.

Step-by-step explanation:

Data given and notation

n=50 represent the random sample taken

X=19 represent the businesses were highly profitable

\hat p=\frac{19}{50}=0.38 estimated proportion of businesses were highly profitable

p_o=0.28 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of businesses were highly profitable is different from 0.28 or no, the system of hypothesis is.:  

Null hypothesis:p=0.28  

Alternative hypothesis:p \neq 0.28  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info required we can replace in formula (1) like this:  

z=\frac{0.38 -0.28}{\sqrt{\frac{0.28(1-0.28)}{50}}}=1.575  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>1.575)=0.115  

So the p value obtained was a very high value and using the significance level given \alpha=0.01 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of businesses were highly profitable is not significantly different from 0.28 or 28%.

4 0
4 years ago
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