7(2+5v)=3v+14
14+35v=3v+14
-3v -3v
14+32v=14
-14 -14
32v=0
÷32 ÷32
v=0
hope this helps!!
<h2><u>Graphing</u></h2>
<h3>The graph of this function is shifted 7 units right and shifted 5 units up.</h3>
<h3>f(x) = -2/3(x - 7)² - 5</h3>
<u>Answer:</u>
<u>Explanation:</u>
- Why false? As I noticed, in the equation f(x) = -2/3(x - 7)² - 5, the vertex is (7, -5). The value of a, which is -2/3, is negative. So the graph opens downwards. The graph shifts 7 units to the right, which is correct, but graphing 5 units up is wrong. Why? 5 is negative, so it should be shifted 5 units down.
Wxndy~~
The answer is 20 because you dive it
Answer:
C
Step-by-step explanation:
Four right angles eliminates trapezoids.
Four right angles also eliminates any triangle
General quadrilaterals should be eliminated by the 4 right angles. If they have 4 right angles, the figure is not a general quadrilateral.
The answer is rectangles and squares.
Answer:
A, C
Step-by-step explanation:
Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.
Examining
A) True
Double angle 
B) False,
No further development towards a Trig Identity
C) True
Double Angle Sine Formula 
D) False No further development towards a Trig Identity
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