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2 years ago

what is 12/3 as an improper fraction? a. 2/3 b. 5/3 c. 8/3 d. 6/3 user: what is 20 × 6? a. 100 b. 40 c. 12 d. 120

1 answer:

7 0

$1\dfrac{2}{3}=\dfrac{1\cdot3+2}{3}=\boxed{\dfrac{5}{3}}\to\fbox{b.}\\\\20\times6=6\cdot(2\cdot10)=6\cdot2\cdot10=12\cdot10=\boxed{120}\to\fbox{d.}$

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A toy store's percent of markup is 45%. A model train costs the store $50. Find the<br> markup.

tia_tia [17]

Answer:

$22.50

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

A hose fills a hot tub at a rate of 2.65 gallons per minute. How many hours will it take to fill a 283 -gallon hot tub?

dsp73

Answer:

you need to substitute values on the next form of resolving this problem as follows...

A hose fills up a hot tub at a rate of 3.2 gallons per minute. How many hours will it take to fill a 300 gallon hot tub?

please explain the method of unit conversions as thoroughly as possible.

Solution:

The rate of fill up is, Rate = 3.2 Gallons / minute = 3.2 g/min

The hut tub volume is 300 Gallons

You can set up this problem as follows:

Every 3.2 gallons require 1 minute, How many minutes 300 gallons require?

3.2 g 1min

300 g ? min = (300 gallons x 1min/ 3.2 gallons)=(300/32)min

= 93.75 min

or simply the number minutes is the time required (T) the rate is (R) and the volume is (V)

such that T=V/R= (300g/3.2 g/min)= 93.75 min

7 0

3 years ago

A coin is tossed four times What is the probability of getting four heads? (1 mark) a) b) What is the probability of getting exa

BlackZzzverrR [31]

<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

$1/2\times1/2\times1/2\times1/2=1/16$

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have $2^{4}$ or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = $\frac{4!}{2!2!}$ = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = $1/2\times1/2\times1/2\times1/2=1/16$

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = $1/16+1/16+1/16+1/16+1/16=5/16$

6 0

3 years ago

1. The amount of extension in an elastic spring varies directly as the weight hung on it. If a weight of 150 gm produces an exte

gregori [183]

Answer:

900 g

Step-by-step explanation:

let e be extension and w be weight

given e varies directly as w then the equation relating them is

e = kw ← k is the constant of variation

to find k use the condition w = 150 , e = 2.9 , then

2.9 = 150k ( divide both sides by 150 )

$\frac{2.9}{150}$ = k , that is

k = $\frac{29}{1500}$

e = $\frac{29}{1500}$ w ← equation of variation

when e = 17.4 , then

17.4 = $\frac{29}{1500}$ w ( multiply both sides by 1500 )

26100 = 29w ( divide both sides by 29 )

900 = w

3 0

2 years ago

Can you please help me with this! It's due in a couple hours.

castortr0y [4]

Answer:

f(2) = -5

Step-by-step explanation:

A point (x, y) lying on a function represents output value (y-value) of the function for any input value (x-value).

In other words y = f(x) for any input value of 'x'.

From the graph attached,

For the input value x = 2,

Output value of the function is y = -5

Therefore, f(2) = -5 will be the answer.

5 0

2 years ago