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Slav-nsk [51]
3 years ago
11

What is the number that follows in this sequence y-1, 2y, -2, 4y-4, 8y-8, __ ??

Mathematics
2 answers:
photoshop1234 [79]3 years ago
7 0
16, because the pattern is to double the number each time. If you liked my answer please mark it the brainiest
Varvara68 [4.7K]3 years ago
4 0
Given the sequence, the rule appears to be 2n.
(Y-1)2 must be distributed. The result is 2Y - 2. 2(2Y-2) = 4Y-4.
2(4Y - 4) = 8Y - 8.
The same rule will apply throughout the sequence.
2(8Y-8) must be distributed. To distribute we multiply the outside number (2) by the inside numbers (8Y-8).
(2x8Y) + (2x-8)
16Y - 16 is our result.
Hope this helps!
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keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

2x+y-3=0\implies y=\stackrel{\stackrel{m}{\downarrow }}{-2} x+3 \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so we're really looking for the equation of a line with a slope of -2 and that passes through (1 , -1)

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad \qquad \stackrel{slope}{m}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{-2}(x-\stackrel{x_1}{1}) \\\\\\ y+1=-2x+2\implies y=-2x+1

8 0
2 years ago
Identify the solution <br> Answer choices<br> 1. 0,3<br> 2. 3, -2<br> 3. 4,2<br> 4 -2,3
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Answer:

2) (3,-2)

Step-by-step explanation:

the solution is where the lines intersect. they intersect at one point because this function is linear. they intersect at the point (3,-2)

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This is a true statement (:
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PIT_PIT [208]

Step-by-step explanation:

the formula is too long so the link is below:

https://www.geteasysoloution.com/1/3x+12=x-4

3 0
3 years ago
The table shows how many books the students in Bergdalsskolan list during the summer. There were 48 students who list 4 books. a
Juliette [100K]

Step 1:

First, find the total number of students.

Let the total number of students = m

Step 2:

Find the total number of students using the percentage of 4 books.

48 students listed 4 books with a percentage of 16%

\begin{gathered} 48\text{ = 16\% of m} \\ 48\text{ = }\frac{16}{100}\text{   }\times\text{  m} \\ 48\text{ = }\frac{16m}{100} \\ \text{Cross multiply} \\ 16m\text{ = 48  }\times\text{  100} \\ 16m\text{ = 4800} \\ \text{m = }\frac{4800}{16} \\ \text{m = 300} \end{gathered}

Hence, there are 300 students.

a)

\begin{gathered} \text{Number of students that had 1 book = 24\% of 300} \\ =\text{ }\frac{24}{100}\text{  }\times\text{  300} \\ =\text{ }\frac{7200}{100} \\ =\text{ 72  students} \end{gathered}

72 students had 1 book.

b) What percentage more read 2 books than 4 books?

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There are 20% students that read 2 books than 4 books.

8 0
1 year ago
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