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3 years ago

14

Alisha asked 120 students what kind of pet they like the most. Exactly 45% of the students said they liked dogs best. What was t

he total number of students who said they liked dogs best?

1 answer:

qwelly [4]3 years ago

6 0

The answer would be 54 students liked dogs the best.

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Which choices are equivalent to the expression below? Check all that apply.<br> 5 square root 3

blsea [12.9K]

Option A: $\sqrt{75}$

Option C: $\sqrt{15} \cdot \sqrt{5}$

Option F: $\sqrt{25} \cdot \sqrt{3}$

Solution:

Given expression is $5 \sqrt{3}$ .

Option A: $\sqrt{75}$

$\sqrt{75}=\sqrt{25\times3}$

$=\sqrt{5^2\times3}$

$=5\sqrt{3}$

Hence $\sqrt{75}$ is equivalent expression of $5 \sqrt{3}$ .

Option B: $\sqrt{45}$

$\sqrt{45}=\sqrt{9\times5}$

$=\sqrt{3^2\times5}$

$=3\sqrt{5}$

Hence $\sqrt{45}$ is not equivalent expression of $5 \sqrt{3}$ .

Option C: $\sqrt{15} \cdot \sqrt{5}$

$\sqrt{15} \cdot \sqrt{5}=\sqrt{15\times5}$

$=\sqrt{75}$

$=5\sqrt{3}$ (proved in option A)

Hence $\sqrt{15} \cdot \sqrt{5}$ is equivalent expression of $5 \sqrt{3}$ .

Option D: $\sqrt{3} \cdot \sqrt{5}$

$\sqrt{3} \cdot \sqrt{5}=\sqrt{3\times5}$

$=\sqrt{15}$

Hence $\sqrt{3} \cdot \sqrt{5}$ is not equivalent expression of $5 \sqrt{3}$ .

Option E: 75

75 is a whole number.

Hence 75 is not equivalent expression of $5 \sqrt{3}$ .

Option F: $\sqrt{25} \cdot \sqrt{3}$

$\sqrt{25} \cdot \sqrt{3}=\sqrt{25\times3}$

$=\sqrt{75}$

$=5\sqrt{3}$ (proved in option A)

Hence $\sqrt{25} \cdot \sqrt{3}$ is equivalent expression of $5 \sqrt{3}$ .

Therefore, $\sqrt{75},\ \ \sqrt{15} \cdot \sqrt{5}, \ \ \sqrt{25} \cdot \sqrt{3}$ are all equivalent expressions of $5 \sqrt{3}$ .

6 0

3 years ago

Minchanka [31]

Answer:

18 feet

Step-by-step explanation:

9/12 = 0.75

24 x 0.75 = 18

8 0

4 years ago

Read 2 more answers

*please help me out if you know how to solve, last person I asked just put a random awnser for point, the problem is bellow and

kicyunya [14]

For both of these, we will divide the wanted outcome by the number of possible outcomes. We will end up with a decimal. A decimal multiplied by 100 becomes a percent.

[a] 50%

$\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{\text{student failed}}{\text{Period 2's class}} =\frac{12}{24} =0.5,\:0.5*100=50\%$

[b] 52%

$\displaystyle \frac{\text{wanted outcomes}}{\text{possible outcomes}} =\frac{\text{student failed from Period 3}}{\text{fails from both classes}} =\frac{13}{25} =0.52,$

$\displaystyle 0.52*100=52\%$

8 0

2 years ago

Please help... I really need this.

valentinak56 [21]

Answer:

$\frac{4x^3-3x^2+5x+6}{x+6}=4x^2-27x+167-\frac{996}{x+6}$

Step-by-step explanation:

The division problem given to us is $(4x^3-3x^2+5x+6)\div (x+6)$ .

To perform the synthetic division, we write out the coefficient of the polynomial. We set the linear factor to zero and solve for x, this becomes our divisor. That is $x+6=0\implies x=-6$ .

We carry out the synthetic division as shown in the attachment.

The result of the synthetic division is 4 -27 167 -996

The first three terms are the coefficients of the quotient and the last term is the remainder.

Therefore the quotient is $q(x)=4x^2-27x+167$ and the remainder is $r(x)=-996$ .

The dividend, the quotient and the divisor are written as

$\frac{4x^3-3x^2+5x+6}{x+6}=4x^2-27x+167-\frac{996}{x+6}$

The correct answer is A

3 0

3 years ago

Please Help! A bag contains four green marbles and five yellow marbles. You randomly select three marbles. What is the probabili

maxonik [38]

Answer:

A. 0.088

B. 0.048

C. 1.83 times

Step-by-step explanation:

From the question given above, the following data were obtained:

Green (G) = 4

Yellow (Y) = 5

Total = 4 + 5 = 9

A. Determination of the probability of selecting three green marbles with replacement.

Green (G) = 4

Yellow (Y) = 5

Total = 9

P(1st G) = 4/9

P(2nd G) = 4/9

P(3rd G) = 4/9

P(all G) = P(1st G) × P(2nd G) × P(3rd G)

P(all G) = 4/9 × 4/9 × 4/9

P(all G) = 64/729

P(all G) = 0.088

B. Determination of the probability of selecting three green marbles without replacement.

Green (G) = 4

Yellow (Y) = 5

Total = 9

P(1st G) = 4/9

P(2nd G) = 3/8

P(3rd G) = 2/7

P(all G) = P(1st G) × P(2nd G) × P(3rd G)

P(all G) = 4/9 × 3/8 × 2/7

P(all G) = 24/504

P(all G) = 0.048

C. Comparing probability of replacement and without replacement.

P(all G with replacement) = A = 0.088

P(all G without replacement) = B = 0.048

A/B = 0.088/0.048

A/B = 1.83

Cross multiply

A = 1.83 × B

Thus,

P(all G with replacement) = 1.83 × P(all G without replacement)

5 0

3 years ago