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3 years ago

WILL GIVE BRAINLIEST! PLEASE HELP ASAP!

Mathematics

2 answers:

julsineya [31]3 years ago

6 0

This should be 11.
Have a nice one! x

aleksandr82 [10.1K]3 years ago

4 0

Answer:

Step-by-step explanation:

Evaluate using

PEMDAS

First we do what is inside of the Parenthesis 12 - 9 = 3

Now we have 2 + 3²

Next is Exponents 3² = 9

Now we have 2 + 9

there is no multiplication or division needed so we go straight to addition

9 + 2 = 11

So we can conclude that the answer is 11

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Find the coordinates of the midpoint of the segment with the given endpoints.

lesantik [10]

Answer:

The midpoint is (4,3)

Step-by-step explanation:

I attached the midpoint formula.

( -1 + 9 ) ( 4 + 2 )

2 2

8 / 2 = 4 6 / 2 = 3

(4,3)

8 0

3 years ago

Log16^*+log4^*+log2^*=7

ale4655 [162]

Answer:

$x = 16$

Step-by-step explanation:

Given

$log_{16}(x) + log_4(x) + log_2(x) = 7$

Required

Solve for x

$log_{16}(x) + log_4(x) + log_2(x) = 7$

Change base of 16 and base of 4 to base 2

$\frac{log_2(x)}{log_2(16)} + \frac{log_2(x)}{log_2(4)} + log_2(x) = 7$

Express 16 and 4 as 2^4 and 2^2 respectively

$\frac{log_2(x)}{log_2(2^4)} + \frac{log_2(x)}{log_2(2^2)} + log_2(x) = 7$

The above can be rewritten as:

$\frac{log_2(x)}{4log_22} + \frac{log_2(x)}{2log_22} + log_2(x) = 7$

$log_22 = 1$

So, we have:

$\frac{log_2(x)}{4*1} + \frac{log_2(x)}{2*1} + log_2(x) = 7$

$\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x) = 7$

Multiply through by 4

$4(\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x)) = 7 * 4$

$log_2(x) + 2}log_2(x) + 4log_2(x) = 28$

$7log_2(x) = 28$

Divide through by 7

$\frac{7log_2(x)}{7} = \frac{28}{7}$

$log_2(x) = 4$

Apply the following law of logarithm:

If $log_ab = c$ Then $b = a^c$

So, we have:

$x = 2^4$

$x = 16$

6 0

3 years ago

Skipping Lunch A nutritionist wishes to determine, within 3%, the true proportion of adults who do not eat any lunch. If he wish

mixas84 [53]

Answer:

A sample of at least 545 adults is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$\pi = 0.15$

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

If he wishes to be 95% confident that his estimate contains the population proportion, how large a sample will be necessary?

We need a sample of at least n.

n is found when M = 0.03. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.15*0.85}{n}}$

$0.03\sqrt{n} = 1.96\sqrt{0.15*0.85}$

$\sqrt{n} = \frac{1.96\sqrt{0.15*0.85}}{0.03}$

$(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.15*0.85}}{0.03})^{2}$

$n = 544.23$

Rounding up

A sample of at least 545 adults is needed.

6 0

3 years ago

HELP PLS THIS IS DUE TODAY. thank u.

garik1379 [7]

Answer: isnt it eleven?

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Atthebeginningofa31-daybillingperiod,Sandrahasanunpaidbalanceof$720onhercreditcard.Threedaysbeforetheendofthebillingperiod,shepa

Pavlova-9 [17]

We need to calculate the average balance per day.

In this case, the billing period has 31 days and Sandras has an unpaid balance of $720 during 28 days and unpaid balance of $720-$400=$320 during 3 days, so the average balance is:

$\text{average balance=}\frac{(720\cdot28+320\cdot3)}{31}=\frac{21120}{31}=681.29$

7 0

1 year ago

Read 2 more answers