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makkiz [27]
2 years ago
10

Polynomials how do I do these what are the answers ?

Mathematics
1 answer:
PtichkaEL [24]2 years ago
8 0

Answer:

for six you got to get rid of the x's first the you it how u normally would

Step-by-step explanation:


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For what value of x is the rational expression below undefined?<br>(3x-12)/(9-x)
wolverine [178]
When x=9 the expression is undefined.

That is because any number over 0 is undefined, including 0/0.
8 0
2 years ago
A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature
Westkost [7]

Answer:

(a) The value of <em>k</em> is \frac{1}{15}.

(b) The probability that at most three forms are required is 0.40.

(c) The probability that between two and four forms (inclusive) are required is 0.60.

(d)  P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 is not the pmf of <em>y</em>.

Step-by-step explanation:

The random variable <em>Y</em> is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of <em>k</em>.

\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}

Thus, the value of <em>k</em> is \frac{1}{15}.

(b)

Compute the value of P (Y ≤ 3) as follows:

P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\   =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 to be the pmf of Y it has to satisfy the conditions:

  1. P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\
  2. \sum P(y)=1

<u>Check condition 1:</u>

y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0

Condition 1 is fulfilled.

<u>Check condition 2:</u>

\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1

Condition 2 is not satisfied.

Thus, P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5 is not the pmf of <em>y</em>.

7 0
2 years ago
The graph of which function passes through (0,3) and has an amplitude of 3?
evablogger [386]
The choices are supposed to be
f(x) = sin x + 3
f(x) = cos x + 3 
f(x) = 3 sin x
f(x) = 3 cos x

The amplitude is the value of the numerical coefficient of sin or cos. The only possible answers are
f(x) = 3 sin x
f(x) = 3 cos x

Next, the function must pass through the point (0,3)
3 sin 0 = 0 and
3 cos = 3

Therefore, the answer is
f(x) = 3 cos x<span />
6 0
3 years ago
Read 2 more answers
A password is 4 characters long and must consist of 3 letters and 1 of 10 special characters. If letters can be repeated and the
Ne4ueva [31]

The number of possibilities for constructing the 4 characters long password with specified conditions is given by: Option C: 703,040

<h3>What is the rule of product in combinatorics?</h3>

If a work A can be done in p ways, and another work B can be done in q ways, then both A and B can be done in p \times q ways.

Remember that this count doesn't differentiate between order of doing A first or B first then doing other work after the first work.

Thus, doing A then B is considered same as doing B then A

We're specified that:

  • The password needs to be 4 characters long
  • It must have 3 letters and 1 of 10 special characters.
  • Repetition is allowed.

So, each of 3 characters get 26 ways of being 1 letter. (assuming no difference is there between upper case letter and lower case letter).

And that 1 remaining character get 10 ways of being a special character.

So, by product rule, this choice (without ordering) can be done in:

26 \times 26 \times 26 \times 10 = 175760 ways.

Now, the password may look like one of those:

  1. L, L, L, S
  2. L, L, S, L
  3. L, S, L, L
  4. S, L, L, L

where S shows presence of special character and L shows presence of letter.

Those 175760 ways are available for each of those four ways.

Thus, resultant number of ways this can be done is:

175760 \times 4 = 703040

Thus, the number of possibilities for constructing the 4 characters long password with specified conditions is given by: Option C: 703,040

Learn more about rule of product here:

brainly.com/question/2763785

5 0
1 year ago
What is the least positive integer by which 24 should be divided so that the resulting integer is a perfect square?
Daniel [21]

Answer: divide by 6?

Step-by-step explanation:

What is the least positive integer by which 24 should be divided so that the resulting integer is a perfect square?

If we actually guess and check by dividing by 1, then 2, then 3, then etc. we will get the answer. I tried and divided by 6, which is 4, which is a perfect square. Do not trust me completely on this, for I am not quite sure.

7 0
1 year ago
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