Helps please!!!!!!!!!…………………….
1 answer:
You might be interested in
This is adding two vectors, one magnitude 300 direction east, and one magnitude 100 direction 30 degrees northeast.
For the resulting sum we can use the Law of Cosines or just add up the components. Let's try it both ways.
Components first. In the east direction we have
300 + 100 cos 30° = 300 + 100(√3/2) = 386.60 miles per hour
In the north direction we have
0 + 100 sin 30° = 100 (1/2) = 50 miles per hour
So a total speed of
sqrt{386.6^2 + 50^2} = 389.82 miles per hour
Answer: 389.82
--------
OK let's try the Law of Cosines. We have sides 300 and 100 and included angle 150°.
<u>Answer</u>
<em>The total displacement of the object is 320 m</em>
<u>Solution-</u>
From the formulas of mechanics,
Where,
s = displacement
u = initial velocity = 0 ( ∵ As the body was in rest in the beginning )
t = time taken = 8 s
a = acceleration = -10 m/s² ( ∵ -ve is because of the downward motion)
Putting all the values,
( ∵ -ve displacement means it is in downwards)