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pogonyaev
3 years ago
8

Solve inverse operation of A - 5/6 = - 3 2/3

Mathematics
1 answer:
gayaneshka [121]3 years ago
3 0

Answer:

- 2 5/6 = A

Step-by-step explanation:

- 3 2/3 + 5/6 = A

- 2 5/6 = A

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Find the perimeter of the figure to the nearest hundredth.
Kryger [21]

Hello!

Your answer should be 26.85.

We can use the formula of pi d or 2 pi r for the circumference.

You would get 5 pi.

But since its not a full circle you would divide it in half and get 2.5 pi.

2.5 pi is equal to 7.85.

Now we can use the equation 7.85 + 7 + 7 + 5

That would equal our answer... 26.85!

Hope this helps!

3 0
3 years ago
100 points!<br> (05.01)Which statement best describes the area of the triangle shown below?
m_a_m_a [10]

Answer:

8

Step-by-step explanation:

4 x 4 = 16 / 2 = 8 since it is half the 4 by 4

5 0
3 years ago
Work out 9/11 x 2/7 so yh
Nesterboy [21]

Answer:

18/77

Step-by-step explanation:

9*2 = 18

11*7= 77

18/77

3 0
3 years ago
Please help me with this and explain how you got the answer. :)
Igoryamba

Answer:

8 1/4

Step-by-step explanation:

6 3/5 ÷ 0.8

6 3/5 = 33/5

0.8 = 8/10

6 3/5 ÷ 0.8

= 33/5 ÷ 8/10

= 33/5 * 10/8 ( Because multiplication and division are inverse operations)

= 33/4

= 8 1/4

=

7 0
3 years ago
Consider an arbitrary ellipse x 2 a 2 + y 2 b 2 = 1. (Assume a, b &gt; 0.) (a) Find a parametrization of the ellipse using the d
uysha [10]

Answer:

α(t) = (-a*Sin(t), b*Cos (t))    where t ∈ [0, 2π]

Step-by-step explanation:

Given an arbitrary ellipse (x²/a²) + (y²/b²) = 1       (a, b > 0)

The parametrization can be as follows

x = -a*Sin(t)

y = b*Cos (t)

then

α(t) = (-a*Sin(t), b*Cos (t))    where t ∈ [0, 2π]

If  t = 0

α(0) = (-a*Sin(0), b*Cos (0)) = (0, b)

If  t = π/2

α(π/2) = (-a*Sin(π/2), b*Cos (π/2)) = (-a, 0)

If  t = π

α(π) = (-a*Sin(π), b*Cos (π)) = (0, -b)

If  t = 3π/2

α(3π/2) = (-a*Sin(3π/2), b*Cos (3π/2)) = (a, 0)

If  t = 2π

α(2π) = (-a*Sin(2π), b*Cos (2π)) = (0, b)

We can see the sketch in the pic.

7 0
3 years ago
Read 2 more answers
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