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erastovalidia [21]
3 years ago
8

The angle of elevation from a point on the ground to the top of a pyramid is 37 degrees 50​' The angle of elevation from a point

183 feet farther back to the top of the pyramid is 18 degrees 10​'. Find the height of the pyramid.

Physics
1 answer:
Serjik [45]3 years ago
5 0

Answer:

The height of the pyramid is approximately 104 Ft. See the graphic attached.

Explanation:

First, you have to plot to realize that you have two rectangle triangles, formed by the different elevation points of view. From there you can have a system of two equations, with two unknown values.

Equation (1)

tan 37^{o}50'= \frac{Ph}{x} \\\\Ph=tan 37^{o}50'  x= 0.7766 x

Equation (2)

tan 18^{o}10'=\frac{Ph}{x+183} \\\\Ph=[tan 18^{o}10'][x+183]=[0.3281][x+183]

Matching (1) and (2)

0.7766 x=0.3281(x+183)\\\\(0.7766-0.3281)x=60.05\\\\x=\frac{60.05}{0.4485} =133.89ft

replacing x value in (1)

Ph=0.7766*133.89=103.9789\\Ph = 104 ft

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A gyroscope flywheel of radius 3.25 cm is accelerated from rest at 11.6 rad/s2 until its angular speed is 1820 rev/min. (a) What
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Explanation:

The given data is as follows.

           radius (r) = 3.25 cm,    \alpha = 11.6 rad/s^{2}

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Putting the given values into the above formula as follows.

         a_{tangential} = \alpha \times r

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Three point charges have equal magnitudes, two being positive and one negative. These charges are fixed to the corners of an equ
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Answer:

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Fn₂= 810 N

Magnitude of the net force on q₃+

Fn₃= 810 N

Explanation:

Look at the attached graphic:

The charges of the same sign exert forces of repulsion and the charges of   opposite sign exert forces of attraction.

Each of the charges experiences 2 forces and these forces are equal and we calculate them with Coulomb's law:

F= (k*q*q)/(d)²

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Magnitude of the net force on q₃+

Fn₃x= 810- 810 cos 60° = 405 N

Fn₃y= 810*sin 60° = 701.5 N

Fn_{3} = \sqrt{405^{2}+701.5^{2}  }

Fn₃ = 810 N

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Elena L [17]

Answer:

D

Explanation:

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3 years ago
Read 2 more answers
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