A cylinder with a moving piston expands from an initial volume of 0.250 L against an external pressure of 2.00 atm. The expansio
1 answer:
The final volume of the gas is 144.25 L
Explanation:
For an ideal gas kept at constant pressure, the work done by the gas on the surroundings is given by
where
p is the pressure of the gas
is the initial volume
is the final volume
For the gas in the cylinder in this problem,
p = 2.00 atm
And we also know the work done,
W = 288 J
So we can solve the equation for , the final volume:
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We can solve the problem by using Newton's second law of motion:
where
F is the net force applied to the object
m is the object's mass
a is the acceleration of the object
In this problem, the force applied to the car is F=1050 N, while the mass of the car is m=760 kg. Therefore, we can rearrange the equation and put these numbers in, in order to find the acceleration of the car:
The equation also tells us that the acceleration and the force have same directions: therefore, since the force exerted on the car is horizontal, the correct answer is
<span>B) 1.4 m/s2 horizontally.</span>
where
F is the net force applied to the object
m is the object's mass
a is the acceleration of the object
In this problem, the force applied to the car is F=1050 N, while the mass of the car is m=760 kg. Therefore, we can rearrange the equation and put these numbers in, in order to find the acceleration of the car:
The equation also tells us that the acceleration and the force have same directions: therefore, since the force exerted on the car is horizontal, the correct answer is
<span>B) 1.4 m/s2 horizontally.</span>
Explanation:
It is known that relation between torque and angular acceleration is as follows.
and, I =
So,
= 4
So,
= 1
as
=
Hence,
Thus, we can conclude that the new rotation is times that of the first rotation rate.