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Kipish [7]
3 years ago
9

What is an easy way to balance chemical equations?

Physics
1 answer:
Lorico [155]3 years ago
8 0

write out what you have on both sides, then just use basic multiplication to try and even out both sides. I can help if you need me to balance some for you!!

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A coin is thrown with a velocity of 0 m/s down a dry well and hits bottom in 1.2s, what’s the depth of the well?
pentagon [3]

Answer:

The well is 7.1 meters deep.

Explanation:

The formula to use here is the distance in a uniformly accelerated motion:

d = \frac{1}{2}at^2+v_0t+d_0

where d stands for distance, t for time, a for acceleration, v0 and d0 for initial velocity and distance, respectively. Since the initial distance and velocity are both zero, we are left with the first term. The coin is in free fall and so it is accelerated by gravity:

d = \frac{1}{2}at^2= \frac{1}{2}gt^2=\frac{1}{2}9.8\frac{m}{s^2}1.2^2s^2=7.1m

The well is 7.1 meters deep.

5 0
4 years ago
4.
xxTIMURxx [149]
Idk what to say to this
3 0
3 years ago
Let x define the position of an object such that x =
timama [110]
See the attached picture for answers

7 0
3 years ago
How much would a 75kg man weigh due to the effect of gravity
Nezavi [6.7K]

Answer: 735 N

Explanation:

Weight W is a measure of the gravitational force acting on an object and is directly proportional to the product of the mass m of the body by the acceleration of gravity g:  

W=m.g

In the case of our planet Earth, the acceleration due gravity is g=9.8 m/s^{2}. So for a man whose mass is m=75 kg, his weight is:

W=(75 kg)(9.8 m/s^{2})

W=735 N

4 0
3 years ago
The electromagnetic wave that delivers a cellular phone callto
spin [16.1K]

Answer:

E=2.41\cdot 10^{-5} J

Explanation:

The intensity of an electromagnetic wave can be expressed in terms of the magnetic field using the next relationship:

I_{average}=\frac{cB_{0}^{2}}{2\mu_{0}} (1)

  • c is the speed of light (3*10⁸ m/s)
  • μ₀ is the permeability of free space (in vacuum ) (1.26*10⁻⁶ N/A²)
  • B₀ is the magnetic field

I_{average}=\frac{3\cdot 10^{8}(1.5\cdot 10^{-10})^{2}}{2\cdot 1.26\cdot 10^{-6}}

I_{average}=2.68\cdot 10^{-6} W/m^{2}

Now, let's define the relationship between power (P) and average intensity (I).

I_{average}=\frac{P}{A}

  • P is the power
  • A is the area crossed

So we can calculate the power.

P=I_{average}\cdot A=2.68\cdot 10^{-6}\cdot 0.20=5.37\cdot 10^{-7} W

Finally, energy is the product of P times time, so:

E=P\cdot t=5.37\cdot 10^{-7} \cdot 45=2.41\cdot 10^{-5} J

I hope it helps you!

5 0
3 years ago
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