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3 years ago

¿Cuál es la aceleración de una bala que sale del cañón de 9 cm a una velocidad de 323 m/s? *

Physics

1 answer:

adelina 88 [10]3 years ago

3 0

Answer:

1.16×10⁶ m/s²

Explanation:

Los siguientes datos se obtuvieron de la pregunta:

Distancia (d) = 9 cm

Velocidad (v) = 323 m/s

Aceleración (a) =.?

A continuación, convertimos 9 cm a metro (m). Esto se puede obtener de la siguiente manera:

100 cm = 1 m

Por lo tanto,

9 cm = 9 cm × 1 m / 100 cm

9 cm = 0.09 m

A continuación, determinaremos el tiempo que tarda la bala en salir del cañón. Esto se puede obtener de la siguiente manera:

Distancia (d) = 0.09 m

Velocidad (v) = 323 m / s

Tiempo (t) =?

Velocidad (v) = Distancia (d) / tiempo

323 = 0.09 / t

Cruz multiplicar

323 × t = 0.09

Dividir ambos lados por 323

t = 0.09 / 323

Tiempo (t) = 2.79 × 10¯⁴ s

Finalmente, determinaremos la aceleración de la bala de la siguiente manera:

Velocidad (v) = 323 m / s

Tiempo (t) = 2.79 × 10¯⁴ s

Aceleración (a) =.?

a = v / t

a = 323 / 2.79 × 10¯⁴

a = 1.16 × 10⁶ m / s²

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