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Stels [109]
2 years ago
13

PLEASE HELP:

Physics
1 answer:
german2 years ago
7 0

Answer:

3.39 mins.

10m/s multiplied by 6 equals to 60 seconds or 1 minute

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A glass ball of radius 3.74 cm sits at the bottom of a container of milk that has a density of 1.04 g/cm3. The normal force on t
Gelneren [198K]

Answer:

The mass of the ball is 0.23 kg

Explanation:

Given that

radius ,r= 3.74 cm

Density of the milk ,ρ = 1.04 g/cm³ = 1.04  x 10⁻³ kg/cm³

Normal force ,N= 9.03 x 10⁻² N

The volume of the ball V

V=\dfrac{4}{3}\pi r^3

V=\dfrac{4}{3}\times \pi \times 3.74^3\ cm^3

V= 219.13 cm³

The bouncy force on the ball = Fb

Fb = ρ V g

Fb  + N = m g

m=Mass of the ball = Density x volume

m = γ V    , γ =Density of the Ball

ρ V g  + N =  γ V g               ( take g= 10 m/s²)

\gamma =\dfrac{N+\rho V g}{V g}

\gamma =\dfrac{9.03\times 10^{-2}+1.04\times 10^{-3}\times 219.13\times  10}{219.13\times 10}

γ = 0.00108 kg/cm³

m = γ V

m = 0.00108 x 219.13

m= 0.23 kg

The mass of the ball is 0.23 kg

5 0
2 years ago
If the distance between two masses is tripled, the gravitational force between changes by a factor of:_______
adell [148]

Answer:

option A

Explanation:

given,

distance between two masses is doubled

new distance, r' = 3 r

using gravitational force equation

F = \dfrac{GMm}{r^2}............(1)

new gravitational force

F' = \dfrac{GMm}{r'^2}

now from the given condition

F' = \dfrac{GMm}{(3r)^2}

F' = \dfrac{GMm}{9r^2}

F' = \dfrac{1}{9}\dfrac{GMm}{r^2}

now, from equation (1)

F' = \dfrac{1}{9}F

\dfrac{F'}{F} = \dfrac{1}{9}

now, the change in gravitational force factor is equal to \dfrac{1}{9}

Hence, the correct answer is option A

3 0
3 years ago
If an object doubles in mass, what happens to its inertia?
son4ous [18]

Inertia is proportional to mass. It is a measure of the resistance to changes in velocity. Inertia is a property of mass and cannot change. Momentum changes as an object changes its velocity.


HENCE The inertia will also be doubled

5 0
3 years ago
Which factor is least likely to limit the rate of photosynthesis?
madreJ [45]

Answer:

oxygen concentration

Explanation:

8 0
3 years ago
You have a string with a mass of 0.0133 kg. You stretch the string with a force of 8.89 N, giving it a length of 1.97 m. Then, y
Kazeer [188]

Answer:

(i) The wavelength is 0.985 m

(ii) The frequency of the wave is 36.84 Hz

Explanation:

Given;

mass of the string, m = 0.0133 kg

tensional force on the string, T = 8.89 N

length of the string, L = 1.97 m

Velocity of the wave is:

V = \sqrt{\frac{F_T}{M/L} } \\\\V = \sqrt{\frac{8.89}{0.0133/1.97} } \ = 36.29 \ m/s

(i) The wavelength:

Fourth harmonic of a string with two nodes, the wavelength is given as,

L = 2λ

λ = L/2

λ = 1.97 / 2

λ = 0.985 m

(ii) Frequency of the wave is:

v = fλ

f = v / λ

f = 36.29 / 0.985

f = 36.84 Hz

3 0
3 years ago
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