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Answer:
A student have to score 1.28 standard deviations above the mean o be publicly recognized.
Step-by-step explanation:
If , then
, is a standard normal variate with mean, E (<em>Z</em>) = 0 and Var (<em>Z</em>) = 1. That is,
.
The distribution of these <em>z</em>-variates is known as the standard normal distribution.
In statistics, a standardized score is the number of standard deviations an observation or data point is above the mean.
Thus, <em>z</em>-scores are a type of standardized scores.
It is provided that the students who score in the top 13 percent in the National Financial Capability Challenge Exam are recognized publicly for their achievement by the Department of the Treasury.
Let <em>x</em> be score of the top 13%.
So, to be are recognized publicly for their achievement by the Department of the Treasury the probability of score <em>x</em> must be:
P (X < x) = 0.90
⇒ P (Z < z) = 0.90
The value of <em>z</em> for the above probability is:
<em>z </em>= 1.28
*Use a <em>z</em>-table.
Thus, a student have to score 1.28 standard deviations above the mean o be publicly recognized.
