All categories

3 years ago

how many minutes is it before 12 noon if 20 minutes ago it was three times as many minutes after 9 am

1 answer:

7 0

First, change everything into minutes.
12 noon is 12 by 60 which = 720 minutes.
9am is 9 by 12 which = 540 minutes.
X is now your number of minutes before noon.So noon - x is the next step:
720 - x
20 minutes ago it was 720 - x - 20
720 - x - 20= 540 + 3x (3x because you're looking for 3 times as many minutes)
720 - 20 - 540=4x (you combine all the like numbers and variables)
160 = 4x
160/4= x
40 = x
Your answer is 40 minutes
<span>
</span>

You might be interested in

To what place is 220.0 accurate?

natulia [17]

the answer of the question is tens

5 0

3 years ago

I need help with all the answers please and thank you

Lapatulllka [165]

Answer:

I think 7=2, 6=-2, 4=23, 8=-7, 3=9, 1=12, 2=0, 5=7, 10=8, 11=3, 12=-45, 9=25

Step-by-step explanation:

I tried my best

7 0

2 years ago

Expand (- 3a - 5x) (- 2b - 4y).

vekshin1

Answer: −3a(−2b−4y).−5x(−2b−4y). to this

6ab+12ay+10bx+20xy

Step-by-step explanation: hope this helps :)

8 0

3 years ago

Read 2 more answers

If Anna have 8000 and gave jim 300 and bought some items a shoes for 290 a suit for 400 and a phone for 2000

vovangra [49]

Answer: Assuming the unit is dollars, the answer would be $5,010.

Explanation:

Step 1: 8000-300 is 7700.

Step 2: 7700-290 is 7410

Step 3: 7410-400 is 7010

Step 4: 7010-2000 is 5010

So, the answer is Anna has $5,010 dollars left after giving Jim $300, buying shoes for $290, a suit for $400 and spending $2,000 dollars on a new phone.

6 0

3 years ago

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,

$undefined$

4 0

1 year ago