Just need to find out under early to add graduate and undergraduate together and then see if how much out of the total of those who registered early is undergraduate
Answer:
We do not see the image
Step-by-step explanation:
Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
Answer:
1) 11
2) 2
3) 
4) 
5) -2
6) 
Step-by-step explanation:
1) 2
+ 3
- 
=(2 × 2
)+ (3 × 4
) - 5
= 4
+ 12
- 5
= 11
2) 4
-2
+ 
= (4 × 2
) - (2 × 7
) + 8
= 8
- 14
+8
= 2
3) 5
- 3
= 5×
- 3×
+ 4×
+ 2×
= 
= 
4) 
= 
= 
5) 
= 
= -2
6) 
= 
= 2×
- 2×
- 
= 
= 
Hope the working out is clear and will help you. :)