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tensa zangetsu [6.8K]
2 years ago
7

g Suppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you re

ad the base titrant volume as 1.94 mL. After running the titration and reaching the endpoint, you read the base titrant volume as 23.82 mL. What volume of base was required for the titration
Chemistry
1 answer:
melamori03 [73]2 years ago
8 0

Answer:

21.88mL is the volume of base required for the titration.

Explanation:

For an acid-base titration trying to find the concentration of an acid, you must add a known quantity of the acid and titrate it with an standarized base.

If you know the moles of base you add to the acid solution, these moles are equal to moles of acid.

In the buret of the titration, initial volume is 1.94mL and final volume is 23.82mL. The volume you are adding is the difference between initial and final volume, that is:

23.82mL - 1.94mL

<h3>21.88mL is the volume of base required for the titration.</h3>
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