Answer:
41.3 s
Explanation:
Let t₁ represent the time taken for SO₂ to effuse.
Let t₂ represent the time taken for Ar to effuse.
Let M₁ represent the molar mass of SO₂
Let M₂ represent the molar mass of Ar
From the question given above,
Time taken (t₁) for SO₂ = 52.3 s
Time taken (t₂) for Ar =?
Molar mass (M₁) of SO₂ = 32 + (16×2) = 32 + 32 = 64 g/mol
Molar mass (M₂) of Ar = 40 g/mol
Finally, we shall determine the time taken for Ar to effuse by using the Graham's law equation as shown below:
t₂ / t₁ = √(M₂ / M₁)
t₂ / 52.3 = √(40 / 64)
t₂ / 52.3 = √0.625
t₂ / 52.3 = 0.79
Cross multiply
t₂ = 52.3 × 0.79
t₂ = 41.3 s
Thus, the time taken for the amount of Ar to effuse is 41.3 s
Answer:
Solid, liquid or gas. So there is movement no matter the state. The key variable is density. The higher the density the less movement. In solids the motion can be so small it's very hard to measure. Gas on the other hand is easy the motion being large. Bear in mind temperature plays a big role. Higher temps bring faster motion. Finally the pressure of the gas brings about less motion the higher it is as the molecules are closer together & can't move as much.
Explanation:
Solution :
Time (sec) Volume of NaOH (mL)
339 26.23
1242 27.80
2745 29.70
4546 3.81
39.81
Now the example of the first order kinetics w.r.t volumetric analysis is :
Here, 
= volume at time 0 = 0
Since the interval is not constant, we take the time interval as
= 1402.3333
≈ 1402 seconds
= 0.001643 x 0.52045
= 0.00082
Therefore, the first order rate constant is k .
Answer:
<h3>The answer is 0.73 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 620 g
volume = 850 mL
We have
We have the final answer as
<h3>0.73 g/mL</h3>
Hope this helps you
