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kherson [118]
3 years ago
11

A sample of copper powder is heated in an evaporating dish using a Bunsen burner. If the mass of the powder in the evaporating d

ish increases after heating, this indicates that A. the copper must have combined with another substance. B. the copper must have lost matter. C. hot copper is more dense than cold copper. D. hot copper weighs more than cold copper.
Chemistry
1 answer:
Charra [1.4K]3 years ago
5 0

Answer : The correct option is, (A) the copper must have combined with another substance.

Explanation :

According to the question, when a sample of copper powder is heated in an evaporating dish by using Bunsen burner then the mass of the powder in the evaporating dish increases after heating that means the copper powder will be combined with the another substance.

If the mass of powder in the evaporating dish is decreases after the heating then the copper powder must have lost some matter.

The given option C and D are wrong statements because the hot copper is less dense than the cold copper and as we know that the density is directly proportional to the mass of a substance that means the hot copper weighs less than cold copper.

Hence, the correct option is, (A) the copper must have combined with another substance.

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I need help with my quiz.
katrin2010 [14]

Answer:

C

Explanation:

4 0
3 years ago
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Calculate the concentration of CO2 in water at 25 degrees Celsius when the pressure of CO2 over the solution is 4.5 atm. At 25 d
OLEGan [10]

Answer : The concentration of CO_2 is, 0.12 M

Explanation :

Using Henry's law :

C_{CO_2}=k_H\times p_{CO_2}

where,

C_{CO_2} = concentration of CO_2 = ?

p_{CO_2} = partial pressure of CO_2 = 4.5 atm

k_H = Henry's law constant  = 3.1\times 10^{-2}mol/L.atm

Now put all the given values in the above formula, we get:

C_{CO_2}=3.1\times 10^{-2}mol/L.atm\times (4.5atm)

C_{CO_2}=0.1395M\approx 0.12M

Thus, the concentration of CO_2 is, 0.12 M

5 0
2 years ago
Can someone plz help me? :(
Snezhnost [94]

Answer:

The answer is a. I learned that they can multiply by using your cells

6 0
2 years ago
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100 POINTS ANSWER FAST
andreev551 [17]
I would say b is the correct answer 
6 0
3 years ago
Read 2 more answers
Question 8 (5 points)
Fynjy0 [20]

[H+][OH-]=10-¹⁴

We are using this formula because we need to find the H+

substitute the value given for hydronium ion for OH-

[H+][4.19×10⁵]=10-¹⁴

[H+]=10-¹⁴÷4.19×10⁵

[H+]=2.387×10-¹⁹

Then the pH of the solution will be

pH= –log¹⁰ [H+]

pH = –log¹⁰ [2.387×10-¹⁹]

pH= –log¹⁰2.387+19log¹⁰

= –0.378+19

pH =18.622

8 0
2 years ago
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