First you need to convert them to the same unit. 1 cm is 10 mm, so the scale is 5:10. 5*2 is 10, so the scale factor is 2.
The perimeter of right isosceles ΔABC with midsegment DE is 16 + 8√2.
If right isosceles ΔABC has hypotenuse length h, then the two other sides are congruent.
side a = side b
Using Pythagorean theorem, c^2 = a^2 + b^2
h^2 = a^2 + b^2 a = b
h^2 = 2a^2
a = h/√2
If DE is a midsegment not parallel to the hypotenuse, then it is a segment that connects the midpoints of one side of a triangle and the hypotenuse. See photo for reference.
ΔABC and ΔADE are similar triangles.
a : b : h = a/2 : 4 : h/2
If a/2 = a/2, then b/2 = 4.
b/2 = 4
b = 8
If a = b, then a = 8.
If a = h/√2, then
8 = h/√2
h = 8√2
Solving for the perimeter,
P = a + b + h
P = 8 + 8 + 8√2
P = 16 + 8√2
P = 27.3137085
To learn more about midsegment: brainly.com/question/7423948
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Oftentimes, it makes the problem much easier to solve and change into other things like ratios, percentages, and decimals.
Answer:
Step-by-step explanation:
<u>Amount paid for food booth</u>
- 15*$100 + 15*d*$5 = 75d + $1500
<u>Amount paid for game booth</u>
- 20*$50 + 20*d*$7 = 140d + $1000
<u>Total amount paid</u>
- 75d + $1500 + 140d + $1000 = 215d + $2500
Answer:

Step-by-step explanation:
Take out 4:
4(x^2-8x)-12
=4(x^2-8x+16-16)-12
=4(x^2-8x+16)-64-12
=4(x^2-4)^2 - 76
=