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astraxan [27]
3 years ago
11

For the standard form of two billion three Hundred fifty thousand four

Mathematics
1 answer:
Drupady [299]3 years ago
5 0
2,250,000,004 if that is what you are looking for<span />
You might be interested in
Solve for the zeros of the quadratic function f(x) = 9x2 + 6x + 1. Write the answer as a fraction.
CaHeK987 [17]

Answer:

x = -1/3

Step-by-step explanation:

x = [-6 +- squareRoot(36-4x9)] / 2 times (-6)

= -6/18 = -1/3

x-(-1/3) = 0 ---> x = -1/3

6 0
3 years ago
Read 2 more answers
4=32b<br> solve for b WILL GIVE BRAINLIEST
Makovka662 [10]

Answer:

1/8

Step-by-step explanation:

32b \div 32 = 4 \div 32 \\

5 0
2 years ago
What is the value of x?<br> What is the measure of angle QOR?<br> What is the measure of angle ROS?
Veseljchak [2.6K]

Answer:

x = 26

angle QOR = 31

angle ROS = 59

Step-by-step explanation:

(x + 5) + (2x + 7)  = 90\\ 2x + x + 5 + 7  = 90 \\ 3x + 12  = 90 \\ 3x  = 90 - 12 \\ 3x = 78 \\ x = 78 \div 3 \\ x = 26

Sub x in

(x + 5) \\ 26 + 5 = 31

and

(2 \times 26 + 7) \\  = 52 + 7 \\  = 59

4 0
2 years ago
ΔMNO is shown.
JulijaS [17]

Answer:

ABC - AAS

DEF - not enough information

GHI - not enough information

JKL - SAS

Step-by-step explanation:

SAS postulate states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent.

AAS postulate states that if two angles and the non-included side one triangle are congruent to two angles and the non-included side of another triangle, then these two triangles are congruent.

HL postulate states that if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent.

ASA postulate states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent.

SSS postulate states that if three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.

1. In triangles MNO and ABC, there are two congruent sides and non-included angle - AAS

2. In triangles MNO and DEF, there are two congruent sides  - there is not enough information

3. In triangles MNO and GHI, there are three congruent angles  - there is not enough information

4. In triangles MNO and JKL, there are two congruent sides and included angle - SAS

5 0
3 years ago
Solve 2x2 + 20x = −38. (1 point)
RoseWind [281]

Answer:

The solutions are x=-5+\sqrt{6}  and x=-5-\sqrt{6}


Step-by-step explanation:

we have

2x^{2} +20x=-38

Divide by 2 both sides

x^{2} +10x=-19 ------> x^{2} +10x+19=0

we know that


The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to


x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}


in this problem we have


x^{2} +10x+19=0

so


a=1\\b=10\\c=19


substitute

x=\frac{-10(+/-)\sqrt{10^{2}-4(1)(19)}}{2(1)}


x=\frac{-10(+/-)\sqrt{100-76}}{2}


x=\frac{-10(+/-)\sqrt{24}}{2}


x=\frac{-10(+/-)2\sqrt{6}}{2}


x1=\frac{-10(+)2\sqrt{6}}{2}=-5+\sqrt{6}


x2=\frac{-10(-)2\sqrt{6}}{2}=-5-\sqrt{6}


8 0
3 years ago
Read 2 more answers
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