Given:
The sample array is
x = [123.6 123.9 123.9 123.7 123.4 123.3 123.3 123.6 123.5 123.9 123.5 123.7 124.4 123.7 123.9 124.0 124.2 123.7 123.8 123.8 124.0 123.9 123.6 124.2 123.4 123.4 123.4 123.4 123.3 123.7
123.5 123.6 124.2 123.9 123.9 123.8 123.9 123.7 123.8 123.8]
From the calculator,
The sample size is
n = 40
The sample mean is
xavg = 123.73
The sample std. deviation is
s = 0.27
The expected population average is
μ = 120
Calculate the test statistic.
z = (xavg - μ)/(s/√n) .
= (123.73 - 120)/(0.27/√40)
= 87.36
The null hypothesis is
H₀: xavg = μ
and the alternate hypothesis is
xavg > μ
At α=0.01 level of significance, the one-tailed test has a rejection region of
α/2 = 0.005.
From standard tables, the test statistic clearly falls in the rejection region.
We should reject the null hypothesis and conclude that xavg > μ.
Answer:
The claim that the mean voltage is 120 V is false at the 0.01 significance level.
Answer:
A
Step-by-step explanation:
Those two lines are the same. If you divide the second equation by 2, you will end up with the first equation. A system of linear equations cannot have two of the same line.
Answer:
y=2
because 4x2 =8 then 8-4 equals to 4 which is what your trying to get
Answer:
0
Step-by-step explanation:
Let X to be a random variable that looks a binomial distribution which denoted the number of employees out of the 281 who earn the prevailing minimum wage or less
The sample size n = 281
The population parameter p = 5% = 0.05
Using normal approximation for the mean.
The standard deviation is:
By using continuity correction; the sample mean x is:
x = 30 - 0.5
x = 29.5
The z statistic test can now be as follows:
Z = 4.23
Thus, the probability that company A will get a discount is
P(X ≥ 30) = P(Z >4.23)
= 1 - P(Z < 4.23)
By using the Excel function for the z score 4.23 i.e. "=1 - NORMSDIST(4.23)" we get;
= 0.0000
Answer:
16
Step-by-step explanation:
You had to multiply 3 by 4 to get the 12 sugar
So what you do to one side you do to the other
4 times 4 which is 16
Hope this helps