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Basile [38]
3 years ago
12

Consider the following hypothesis test: H0: = 18 Ha: ≠ 18 A sample of 48 provided a sample mean LaTeX: \overline{x}x ¯ = 17 and

a sample standard deviation s = 4.5. Use LaTeX: \alphaα = 0.05. a. Compute the value of the test statistic.
Mathematics
1 answer:
igomit [66]3 years ago
4 0

Answer:

The value of the test statistic is t = -1.54

Step-by-step explanation:

In this problem, we have that:

Null hypothesis

H_{0} = 18

Alternate hypothesis

H_{a} \neq 18

Compute the value of the test statistic.

This is the value of t, given by

t = \frac{\overline{x} - \mu_{0}}{\frac{s}{\sqrt{n}}}

In this problem, we have that:

\overline{x} = 17, \mu_{0} = 18, s = 4.5, n = 48.

So

t = \frac{17- 18}{\frac{4.5}{\sqrt{48}}} = -1.54

The value of the test statistic is t = -1.54

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elixir [45]

Answer:

(1) TRUE.

(2) FALSE.

(3) FALSE.

(4) TRUE.

(5) FALSE.

Step-by-step explanation:

(1) \sqrt{32} = 2^{\frac{5}{2} }

2^{\frac{5}{2} } = (\sqrt{2} )^5 = (\sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2}) = 4\sqrt{2}\\\\\sqrt{32} = \sqrt{16 \ \times \ 2}\ =  \ \sqrt{16} \ \times \ \sqrt{2} \ = \ 4\sqrt{2}

Thus, the equation is TRUE.

(2) 16^{\frac{3}{8} } = 8^2

16^{\frac{3}{8} } =(2^4)^{\frac{3}{8} } = 2^\frac{3}{2} }= (\sqrt{2} )^3 = (\sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2}) = 2\sqrt{2} \\\\8^2 = 64

Thus, the equation is FALSE.

(3) 4^{\frac{1}{2} } = \sqrt[4]{64}

4^{\frac{1}{2} }= \sqrt{4} = 2\\\\\sqrt[4]{64}  = (64)^{\frac{1}{4} } = (2^6)^{\frac{1}{4} }= 2^{\frac{6}{4} } = 2^{\frac{3}{2} }=(\sqrt{2} )^3 = (\sqrt{2}  \times \sqrt{2}  \times \sqrt{2} ) = 2\sqrt{2}

Thus, the equation is FALSE.

(4) 2^8 = (\sqrt[3]{16} )^6

2^8 = 256\\\\ (\sqrt[3]{16} )^6 = (16)^{\frac{6}{3} } = (2^4)^{\frac{6}{3} } = (2)^{\frac{24}{3} } = 2^8 = 256

Thus, the equation is TRUE.

(5) (\sqrt{64} )^{\frac{1}{3} } = 8^{\frac{1}{6} }\\\\

8^{\frac{1}{6} } = (2^3)^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} } = \sqrt{2} \\\\(\sqrt{64} )^{\frac{1}{3} } = (2^6)^{\frac{1}{3} } = 2^{\frac{6}{3} } = 2^2 = 4

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Answer:

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Step-by-step explanation:

In the given circle O,

Since, RS║VU, and VR is a transverse,

Therefor, m∠V + m∠R = 180° [Consecutive interior angles]

m∠R + 103° = 180° [m∠R = 103° given]

m∠R = 180° - 103°

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Since m∠R = m∠VRT + m∠TRS

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