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galben [10]
2 years ago
13

Draw the structures of the aldol addition and condensation products of cyclopentanone

Chemistry
1 answer:
Ne4ueva [31]2 years ago
8 0

The term aldol condensation has to do with a reation in which a nucleophile attacks the carbonyl group of an aldehyde.

<h3>What is alodol condensation?</h3>

The term aldol condensation has to do with a reation in which a nucleophile attacks the carbonyl group of an aldehyde or a ketone to convert it to the enolate from which attacks another aldehyde or ketone at the carbonyl carbon to form the required product.

The structure of the organic product from the aldol condensation involving cyclopentanone is shown in the image attached to this answer.

Learn more about aldol condensation: brainly.com/question/9415260?:

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Answer:

The amount/type of stain

Explanation:

You would want to ensure that the stain was the same in both samples.  

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What is the smallest particle of a covalent compound that has the properties of that compound?
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3 years ago
Calculate the number of moles of a gas that is present in a 7.55 L container at 45°C, if the gas exerts a pressure of 725mm Hg.
vovikov84 [41]

<u>Answer:</u> The number of moles of gas present is 0.276 moles

<u>Explanation:</u>

To calculate the number of moles of gas, we use the equation given by ideal gas:

PV = nRT

where,

P = Pressure of the gas = 725 mm Hg

V = Volume of the gas = 7.55 L

n = number of moles of gas = ?

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

T = Temperature of the gas = 45^oC=(45+273)K=318K

Putting values in above equation, we get:

725mmHg\times 7.55L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 318K\\\\n=0.276mol

Hence, the number of moles of gas present is 0.276 moles

4 0
3 years ago
What is the density of a gas at 242.5K and 0.7311atm. The molar mass of this gas is 70.90g/mol
Pie

Answer:

0.384g/l

Explanation: the density version of the ideal gas law is pm=drt

in which p= pressure, m=molar mass,d=, density, r= to a constant which is 0.08206, and t=temperature so just input the values

PM=DRT. so to find d the formula would be D=RT\PM

D=<u>0.08206*242.5</u>

        0.7311*70.90

D=0.384g/l

4 0
3 years ago
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