To answer this question, subtract from the total population of 1000 the homozygous dominant (DD) frogs of 280 and the homozygous recessive (dd) frogs of 220, and you are left with 500 frogs that by default are <span>heterozygotes (dD). The frequency of these frogs would be 500/1000 = 0.5</span>
the answer is B. please let me know weather its right or wrong
Answer:
A) nutrient A only
Explanation:
In this case, enzyme A is required for the digestion of nutrient A, thereby evidencing that the mutation affects the enzymatic pathway and the mutant strain only can grow by supplementation with this nutrient. In molecular biology, mutant strains are useful to study enzymatic functions (for instance, the role of enzyme A in nutrient assimilation), as well as to examine downstream signaling pathways.
In experimental design, spontaneous mutations are induced to study their effects on the phenotype. Subsequently, reverse mutations may also be induced to reverse the forward mutation, thus restoring the original wild-type phenotype.
