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3 years ago

How can you change the phases of matter using thermal energy

Physics

1 answer:

Leokris [45]3 years ago

8 0

Answer:

These energy exchanges are not changes in kinetic energy. They are changes in bonding energy between the molecules. If heat is coming into a substance during a phase change, then this energy is used to break the bonds between the molecules of the substance.

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coasting due west on your bicycle at 8 m/s, you encounter a sandy patch of road 7.2m across. when you leave the sandy patch your

LuckyWell [14K]

Its acceleration in the sandy patch is $1.5 m/s^2$

Explanation:

The average speed

$V = (v1 + v2) / 2 = (8 + 6.5) / 2 = 7.25 m/s \\$

Time to pass patch

$t = 7.2 / 7.25 = .993 sec \\$

The acceleration

$a = (v2 - v1) / t = (6.5 - 8) / .993 = -1.51 m/s^2 or 1.5 m/s^2$

Hence, $1.5 m/s^2$ that the acceleration in the sandy patch.

<h3>What do you understand by the acceleration? </h3>

Any procedure where the velocity varies is referred to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.

The meter per second per second (m/s2) unit of acceleration. Definition. The newton is the unit of force that, when applied to a mass of one kilogram, results in a one-meter-per-second acceleration.

Changing the speed at which an object is travelling is what acceleration is all about. A substance is not accelerating if its velocity is not changing.

To learn more about the acceleration, Visit: brainly.com/question/190239

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5 0

2 years ago

A block of mass m is compressed against a spring (spring constant kk) on a horizontal frictionless surface. The block is then re

Nimfa-mama [501]

Answer:

A) True, B) False, C) False and D) false

Explanation:

Let's solve the problem using the law of conservation of energy to know if the statements are true or false

Let's look for mechanical energy

Initial

Emo = Ke = ½ k Dx2

Final

Em1= ½ m v12

Emo = Em1

½ k Δx2 = ½ m v₁²

v₁² = k / m Δx²

v₁ = √ k/m Δx

Now let's calculate the speed when it falls

Vfy² = Voy² - 2gy

Vfy² = - 2gy

Vf² = v₁² + vfy²

A) True v₁ = A Δx

.B) False. As there is no rubbing the mechanical energy conserves

.C) False the velocity is proportional to the square root of the height

v2y = v2 √2

. D) false promotional compression speed

3 0

3 years ago

If for every action force an equal and opposite reaction force exists, how can anything ever be accelerated?

Anon25 [30]

The action and reaction forces act on different objects, therefore the net force is not always zero

Explanation:

Newton's third law of motion states that:

<em>"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"</em>

From the statement above, it is clear that the action and the reaction forces act on different objects. In fact, the action force acts on object B, while the reaction force acts on object A. This means that the two forces never appear in the same free-body diagram of the same object, and therefore when computing the net force acting on an object, we take into account only one of the two forces, never both.

For instance, imagine you are pushing a box along the floor with a force F (action). The box is exerting back on you a reaction force of equal magnitude in the opposite direction, - F. However, if we want to compute the net force on the box, we just take into account the action (F), not the reaction, because the reaction is acting on you, not on the box.

Therefore, the correct answer is

The action and reaction forces act on different objects, therefore the net force is not always zero

Learn more about Newton's third law:

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3 0

3 years ago

If the mass of the ladder is 12.0 kgkg, the mass of the painter is 55.0 kgkg, and the ladder begins to slip at its base when her

Marysya12 [62]

Answer:

μ = 0.336

Explanation:

We will work on this exercise with the expressions of transactional and rotational equilibrium.

Let's start with rotational balance, for this we set a reference system at the top of the ladder, where it touches the wall and we will assign as positive the anti-clockwise direction of rotation

fr L sin θ - W L / 2 cos θ - W_painter 0.3 L cos θ = 0

fr sin θ - cos θ (W / 2 + 0,3 W_painter) = 0

fr = cotan θ (W / 2 + 0,3 W_painter)

Now let's write the equilibrium translation equation

X axis

F1 - fr = 0

F1 = fr

the friction force has the expression

fr = μ N

Y Axis

N - W - W_painter = 0

N = W + W_painter

we substitute

fr = μ (W + W_painter)

we substitute in the endowment equilibrium equation

μ (W + W_painter) = cotan θ (W / 2 + 0,3 W_painter)

μ = cotan θ (W / 2 + 0,3 W_painter) / (W + W_painter)

we substitute the values they give

μ = cotan θ (12/2 + 0.3 55) / (12 + 55)

μ = cotan θ (22.5 / 67)

μ = cotan tea (0.336)

To finish the problem, we must indicate the angle of the staircase or catcher data to find the angle, if we assume that the angle is tea = 45

cotan 45 = 1 / tan 45 = 1

the result is

μ = 0.336

5 0

4 years ago

Calcula la densidad del hierro , si 393 g ocupan un volumen de 50 ml

eimsori [14]

Density is mass over volume: d=m/v
d = 393/50 => d = 7.86 g/ml

7 0

3 years ago