The formula of a compound indicates of all of the following except
1 answer:
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Answer:
Total pressure 5.875 atm
Explanation:
The equation for above decomposition is
rate constant
Half life
Initial pressure
Pressure after 3572 min = P
According to first order kinematics
solving for P we get
P = 2.35 atm
initial 4.70 0 0
change -2x +2x +x
final 4.70 -2x 2x x
pressure of after first half life = 2.35 = 4.70 - 2x
x = 1.175
pressure of after first half life = 2x = 2(1.175) = 2.35 ATM
Total pressure = 2.35 + 2.35 + 1.175
= 5.875 atm
Answer:
Y = 92.5 %
Explanation:
Hello there!
In this case, since the reaction between lead (II) nitrate and potassium bromide is:
Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:
Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:
And the resulting percent yield:
Regards!
Answer: The equivalent mass of the acid is 83.16 grams
Explanation:
To calculate the number of moles for given molarity, we use the equation:
Molarity of solution = 0.1165 M
Volume of solution = 24.68 mL = 0.02468 L
Putting values in equation 1, we get:
( as acidity of NaOH is 1)
For end point: gram equivalents of acid = gram equivalents of base =
Mass of acid=
Thus equivalent mass of the acid is 83.16 grams