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romanna [79]
3 years ago
8

The movement of rocks and soil is an example of

Chemistry
2 answers:
meriva3 years ago
6 0

Answer:

1. C (deposition)

2.  C (Thawing Causes rock particles to move from place to place)

3. Glaciers were moving along, right? so it has to be U shaped since it was a big hunk of ice moving around lol ( my backyard was formed by a glacier so)

brainliest ? :')

Georgia [21]3 years ago
5 0
Disposition

Can you mark brainliest :)
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The balanced chemical equation for the reaction between PCl5 and water is given below. If 3.45 moles of HCl are produced, how ma
enyata [817]
The coefficients of the substances give you the ratio of the number of moles.
The 4 before the H2O and the 5 before the HCl tell you that for every 5 moles of HCl created, 4 moles of H2O had to react.

Therefore:
(3.45mol HCl)(\frac{4 mol H2O}{5 mol HCl})
can be used to find the moles of H2O that react.

(3.45mol HCl)(\frac{4 mol H2O}{5 mol HCl}) = 2.76 mol H20
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3 years ago
Need the answer please. For homework.
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3 years ago
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one beaker contains nacl and another sugar, describe an experiment you could conduct to find the contents
Morgarella [4.7K]

Explanation:

Hi! I don't know why I am not getting any brainliest answer and if you are kind enough could you please mark me as the brainliest answer and please follow me also.

4 0
3 years ago
Air containing 0.06% carbon dioxide is pumped into a room whose volume is 12,000 ft3. The air is pumped in at a rate of 3,000 ft
castortr0y [4]

Answer:

A(t)=1.8+34.2*e^{-t}

Explanation:

The concentration of CO2 in the room will be the amount of CO2 in the room at time t, divided by the volume of the room.

Let A(t) be the amount of CO2 in the room, in ft3 CO2.

The air entering the room is 3000 ft3/min with 0.06% concentrarion of CO2. That can be expressed as (3000*0.06/100)=1.8 ft3 CO2/min.

The mixture leaves at 3000 ft3/min but with concentration A(t)/V. We can express the amount of CO2 leaving the room at any time is A(t).

We can write this as a differential equation

dA/dt=v_i-v_o=1.8-A

We can rearrange and integrate

dA/dt=v_i-v_o=1.8-A\\\\dA/(A-1.8)=-dt\\\\\int(dA/(A-1.8) = -\int dt\\\\ln(A-1.8)=-t+C\\\\A-1.8=e^{-t}* e^{C}=C*e^{-t}\\\\A=1.8+C*e^{-t}

We also know that A(0) = 12000*(0.3/100)=36 ft3 CO2.

A(0)=1.8+C*e^{-0}\\36=1.8+C*1\\C=34.2

Then we have the amount A(t) as

A(t)=1.8+34.2*e^{-t}

5 0
3 years ago
The electron configuration for Helium (He) is shown below.
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Helium has an atomic number 2 and an atomic weight of 4 grams per mole. It is one of the noble gas (which means that it is stable) and also a nonmetal. Its electron configuration is 1s2. There are energy levels and they are s, p, d and f. The s level means that its maximum number of electrons is only 2.
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