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Ulleksa [173]
3 years ago
11

A rectangular field has an area of 1764 m^2 the width of the field is 13 m more than the length what is the perimeter of the fie

ld

Mathematics
1 answer:
ruslelena [56]3 years ago
6 0

Answer:

hello : here is a solution



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Given f(x)=e^-x^3 find the vertical and horizontal asymptotes
Aleonysh [2.5K]

Given:

f\mleft(x\mright)=e^{-x^3}

To find the vertical and horizontal asymptotes:

The line x=L is a vertical asymptote of the function f(x) if the limit of the function at this point is infinite.

But, here there is no such point.

Thus, the function f(x) doesn't have a vertical asymptote.

The line y=L is a vertical asymptote of the function f(x) if the limit of the function (either left or right side) at this point is finite.

\begin{gathered} y=\lim _{x\rightarrow\infty}e^{-x^3} \\ =e^{-\infty} \\ y=0 \\ y=\lim _{x\rightarrow-\infty}e^{-x^3} \\ y=e^{\infty} \\ =\infty \end{gathered}

Thus, y = 0 is the horizontal asymptote for the given function.

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1 year ago
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The answer should be -192. I could explain in the comments if you would like. :)
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3 years ago
Which quadrilaterals are considered parallelogram
Elenna [48]

Answer: Rectangle, Rhombus, Square

Step-by-step explanation:

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3 years ago
Ella used 37.2 pounds of apples to make applesauce . She used one -tenth as a many pounds of sugar as pounds of apples . How man
sukhopar [10]
You would have to divide 37.2 by 10. The answer would be 3.72.
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3 years ago
The perimeter of a rectangular field is 374 yard. If the length of the field is 99 yards, what is its width?
likoan [24]
The perimeter of a rectangle is 2*L+2*W. Knowing that length is 99, we do 2*99 to get 198.Do 374-198, which is 176, we know that that is twice the length of the width. Therefore the width is 176/2, which is 88.
3 0
3 years ago
Read 2 more answers
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